Uniform Circular Motion Formula Notes for NEET Students
- Dr.Sanjaykumar pawar
UNIFORM CIRCULAR MOTION
│
├── Centripetal Acceleration
│ │
│ ├── Definition
│ │ └── Acceleration towards centre
│ │
│ ├── Formula
│ │ └── ac = v² / R
│ │
│ ├── Direction
│ │ ├── Towards centre
│ │ └── Centre-seeking
│ │
│ ├── Nature
│ │ ├── Magnitude constant
│ │ ├── Direction changes
│ │ └── Not a constant vector
│ │
│ └── Proposed By
│ ├── Isaac Newton
│ └── Christiaan Huygens
│
├── Angular Distance
│ │
│ ├── Symbol
│ │ └── Δθ
│ │
│ └── Meaning
│ └── Angle turned by radius vector
│
├── Angular Speed (ω)
│ │
│ ├── Definition
│ │ └── Rate of change of angular displacement
│ │
│ ├── Formula
│ │ └── ω = Δθ / Δt
│ │
│ ├── SI Unit
│ │ └── rad s⁻¹
│ │
│ └── Relation with Frequency
│ └── ω = 2πν
│
├── Linear Speed (v)
│ │
│ ├── Formula
│ │ └── v = Δs / Δt
│ │
│ ├── Arc Length Relation
│ │ └── Δs = RΔθ
│ │
│ └── Relation with Angular Speed
│ └── v = Rω
│
├── Centripetal Acceleration Using Angular Speed
│ │
│ └── Formula
│ └── ac = ω²R
│
├── Time Period (T)
│ │
│ ├── Definition
│ │ └── Time for one revolution
│ │
│ └── Relation
│ └── T = 1/ν
│
├── Frequency (ν)
│ │
│ ├── Definition
│ │ └── Revolutions per second
│ │
│ ├── Formula
│ │ └── ν = 1/T
│ │
│ └── Unit
│ └── Hertz (Hz)
│
├── One Complete Revolution
│ │
│ ├── Distance Covered
│ │ └── s = 2πR
│ │
│ ├── Speed Formula
│ │ └── v = 2πR / T
│ │
│ └── Speed Using Frequency
│ └── v = 2πRν
│
├── Centripetal Acceleration Using Frequency
│ │
│ └── Formula
│ └── ac = 4π²ν²R
│
├── Important NEET Concepts
│ │
│ ├── Speed constant
│ ├── Velocity changes
│ ├── Velocity tangent to path
│ ├── Acceleration towards centre
│ ├── Angular speed measures angular motion
│ └── Circular motion is accelerated motion
│
├── Important Formula Summary
│ │
│ ├── ac = v²/R
│ ├── v = Rω
│ ├── ac = ω²R
│ ├── ω = 2πν
│ ├── ν = 1/T
│ ├── v = 2πR/T
│ ├── v = 2πRν
│ └── ac = 4π²ν²R
│
└── Memory Tricks
│
├── Velocity → Tangent
├── Acceleration → Centre
├── v = Rω
└── ac = ω²R
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| Uniform Circular Motion showing velocity tangent to the circle and centripetal acceleration directed towards the centre. |
Internal Links
Motion in a Plane Notes
Projectile Motion Complete Notes
Laws of Motion NEET Notes
Kinematics Formula Sheet
Vectors in Physics Explained
Circular Motion MCQs for NEET
Angular Velocity and Rotational Motion
Newton’s Laws of Motion Notes
Relative Velocity Notes
Physics Chapter Wise NEET Questions
Uniform Circular Motion — Angular Speed, Time Period and Frequency
Centripetal Acceleration
When an object moves in a circular path with speed v and radius R, the acceleration acting on it is called centripetal acceleration.
Where:
- ac = centripetal acceleration
- v = speed of object
- R = radius of circular path
Direction of Centripetal Acceleration
- The acceleration always acts towards the centre of the circle.
- Therefore it is called centripetal acceleration.
- The word centripetal means "centre-seeking".
Why Direction Changes?
As the object moves around the circle:
- Direction of velocity changes continuously.
- Therefore acceleration direction also changes continuously.
- At every point, acceleration points towards the centre.
Historical Information
- The term centripetal acceleration was proposed by Isaac Newton.
- Detailed analysis was first published by Dutch scientist Christiaan Huygens in 1673.
Angular Distance
When an object moves from one point to another in a circular path, the radius vector turns through some angle.
This angle is called angular displacement or angular distance.
Angular Speed
Angular speed tells us how fast the angle changes with time.
Where:
- ω = angular speed
- Δθ = angular displacement
- Δt = time interval
SI Unit of Angular Speed
Relation Between Linear Speed and Angular Speed
Suppose:
- Distance travelled along circle = Δs
We know:
Also:
Substituting:
Therefore:
Centripetal Acceleration in Terms of Angular Speed
We know:
Using:
Substituting:
Time Period (T)
The time taken by an object to complete one revolution is called time period.
Frequency (ν)
The number of revolutions completed in one second is called frequency.
Relation Between Frequency and Time Period
Distance Covered in One Revolution
In one complete revolution, the object covers the circumference of the circle.
Speed in Terms of Time Period
We know:
Distance in one revolution:
Time taken:
Therefore:
Speed in Terms of Frequency
Since:
Therefore:
Angular Speed in Terms of Frequency
In one revolution:
Therefore:
Centripetal Acceleration in Terms of Frequency
Using:
and
Substituting:
Important Formula Summary
| Formula Name | Formula |
|---|---|
| Linear speed | v = Rω |
| Angular speed | ω = Δθ / Δt |
| Centripetal acceleration | ac = v² / R |
| Acceleration using angular speed | ac = ω²R |
| Frequency relation | ν = 1 / T |
| Angular speed using frequency | ω = 2πν |
| Linear speed using frequency | v = 2πRν |
| Acceleration using frequency | ac = 4π²ν²R |
NEET Important Points
- Velocity acts along tangent to circle.
- Centripetal acceleration acts towards centre.
- Speed remains constant but velocity changes.
- Angular speed measures rate of angular displacement.
- Frequency means revolutions per second.
- Time period means time for one revolution.
Memory Tricks
Acceleration → Centre
Formula Memory Tricks
- v = Rω → "Velocity equals omega R"
- ac = ω²R → "Acceleration equals omega square R"
- ν = 1/T → "Frequency is inverse of time period"
Angular Speed, Time Period and Frequency
Questions and Answers for CBSE Class 11
Multiple Choice Questions (MCQs)
B. Tangential acceleration
C. Centripetal acceleration
D. Gravitational acceleration
B. v²/R
C. R²/v
D. R/v²
B. β
C. ω
D. ν
B. rad/s
C. m
D. Hz
B. v = Rω
C. v = R/ω
D. v = ω²R
Very Short Answer Questions
Short Answer Questions
| Time Period | Frequency |
|---|---|
| Time for one revolution | Revolutions per second |
| Represented by T | Represented by ν |
| Unit = second | Unit = hertz |
2. Its direction changes continuously.
The distance travelled in circular motion is related to angular displacement by:
Dividing by time:
Thus linear speed equals radius multiplied by angular speed.
Long Answer Questions
Suppose an object moves through angular displacement Δθ in time Δt.
Distance travelled along arc:
Linear speed:
Substituting value of Δs:
Therefore:
Hence proved.
We know:
Using relation:
Substitute in formula:
Hence proved.
Distance covered in one revolution:
Time for one revolution:
Therefore:
Since:
Therefore:
Hence proved.
Assertion and Reason Questions
Reason (R): Velocity changes continuously in circular motion.
Reason (R): Equal angles are covered in equal intervals of time.
Reason (R): Frequency is number of revolutions per second.
Fill in the Blanks
Match the Following
| Column A | Column B |
|---|---|
| 1. Angular speed | a. Revolutions per second |
| 2. Time period | b. rad/s |
| 3. Frequency | c. Time for one revolution |
| 4. Centripetal acceleration | d. Towards centre |
1 → b
2 → c
3 → a
4 → d
Statement-Based Questions
1. Angular speed is measured in rad/s.
2. Frequency is inverse of time period.
3. Velocity remains constant in circular motion.
4. Centripetal acceleration acts towards centre.
A. Frequency is measured in hertz
B. Time period is time for one revolution
C. Angular speed is measured in metres
D. Centripetal acceleration acts towards centre

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