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Units and Measurements Class 11 CBSE Physics Exemplar Question & Answer Book with Solutions

  NCERT Class 11 Physics Exemplar solutions helping students master concepts with clear problem-solving practice. Dr.Sanjaykumar Pawar   Units And Measurements    Units and Measurements MCQs with Solutions Units and Measurements - MCQs with Step-by-Step Solutions Q.1 The number of significant figures in 0.06900 is (a) 5 (b) 4 (c) 2 (d) 3 Thinking Process If the number is less than 1, the zeros before the first non-zero digit are not significant. Trailing zeros after a decimal point are significant. Number = 0.06900 0 → Not significant 0 → Not significant 6 → Significant 9 → Significant 0 → Significant 0 → Significant Total significant figures = 4 Answer: (b) 4 Q.2 The sum of the numbers 436.32, 227.2 and 0.301 in appropriate significant figures is (a) 663.821 (b) 664 (c) 663.8 (d) 663.82 Step 1: Add the Numbers 436.32 + 227.2 + 0.301 = 663.821 Step 2: Apply Significant Figure Rule For addition and subtraction, the result should h...
  Class XI Physics Summer Assignment - Subject Enrichment Activity I Class XI Physics Summer Assignment Subject Enrichment Activity – I Q.1 Define Significant Figure? Write down one example. Definition: Significant figures are the meaningful digits in a measured or calculated quantity which are known with certainty plus one final digit that is estimated or uncertain. They indicate the precision of a measurement. Example: In the measurement 2.308 cm , there are 4 significant figures (2, 3, 0 and 8). Q.2 List two commonly used practical units. How are these units related to S.I. units? Light Year (ly): Used for large astronomical distances. Relation with SI unit: 1 light year ≈ 9.46 × 10 15 m Horsepower (hp): Used for power. Relation with SI unit: 1 hp = 746 W Q.3 Define practical units of distance: Light Year and Parallactic Second (Parsec). Light Year (ly): It is the distance travelled by light in vacuum in one year. Parsec (pc): It...

Circular Motion Class 11 Physics Notes | CBSE & NEET Complete Guide

NEET Circular Motion Chapter Explained | Class 11 Physics Study Material  - Dr.Sanjaykumar Pawar  Circular Motion in Physics: Centripetal force keeps objects moving in a circular path towards the center. 🔷 INTERNAL LINK  You can link this page to: /class-11-physics-laws-of-motion /centripetal-force-formula-explained /banking-of-roads-physics-notes /neet-physics-important-formulas /class-11-physics-chapter-4-notes /mcq-on-laws-of-motion-class-11 /physics-revision-notes-neet Circular Motion - NEET Notes NEET Physics Notes - Circular Motion 1. What is Circular Motion? Circular motion is the motion of an object along a circular path. Examples: Stone tied to a string and rotated. Car taking a circular turn. Planet revolving around the Sun. Satellite moving around Earth. 2. Centripetal Acceleration While moving in a circle, the direction of velocity continuously changes. Therefore the object experiences acceleration. This acceleration is ...

CBSE Class 11 Physics Question Bank: Rolling Friction (With Answers)

  Rolling Friction Question Bank – CBSE 11 & NEET Foundation Rolling Friction – Easy NEET Notes  Surface deformation at the contact area is the primary mechanism that generates rolling resistance (friction). - Dr.Sanjaykumar Pawar  1. Rolling Without Slipping When a ring, wheel, or sphere rolls on a horizontal surface without slipping , ideally there should be no frictional force . At any instant, only one point of the body touches the ground . This contact point is momentarily at rest with respect to the ground. Since there is no relative motion at the contact point, kinetic friction does not act . In the ideal case, static friction is also zero . Therefore, the body should continue moving with constant velocity according to Newton's First Law. NEET Point Pure rolling without slipping on an ideal surface requires no friction force. 2. Why Does a Rolling Body Stop in Real Life? In practical situations, a rolling wheel or ball eventually slows down...

Block and Trolley System NEET Solution | Acceleration & Tension Explained

NEET Physics Example 4.9: Block and Trolley System (Step-by-Step) - Dr.Sanjaykumar Pawar  INTERNAL LINKS  /neet-physics-newtons-laws /friction-notes-class-11 /tension-in-string-problems /pulley-system-problems-neet /mechanics-important-questions /class-11-physics-motion-in-a-line /neet-important-derivations Physics NEET diagram showing a block and trolley system with forces, tension, friction, and acceleration clearly labeled.         Example 4.9 – Block and Trolley System Example 4.9 – Block and Trolley System (Easy NEET Notes) Given: Mass of hanging block, \( m_1 = 3\,kg \) Mass of trolley, \( m_2 = 20\,kg \) Coefficient of kinetic friction, \( \mu_k = 0.04 \) Acceleration due to gravity, \( g = 10\,m\,s^{-2} \) String is light (massless) and inextensible Pulley is smooth (frictionless) To Find: Acceleration of the system \( a \) Tension in the string \( T \) Step 1: Understand the Motion The 3 kg block hangs vert...

Coefficient of Static Friction from Angle of Repose: Solved Example

  How to Calculate Static Friction Using Inclined Plane Angle -Dr.Sanjaykumar Pawar  Internal Links Laws of Friction Explained Static vs Kinetic Friction Free Body Diagrams in Physics Inclined Plane Problems and Solutions Newton's Laws of Motion Force Equilibrium Concepts Applications of Friction in Daily Life JEE Mechanics Important Questions NEET Physics Friction Chapter Notes Work, Energy and Power Fundamentals Free-body diagram of a block on an inclined plane showing the relationship between angle of repose and coefficient of static friction. Example 4.8 - Coefficient of Static Friction Example 4.8 A mass of 4 kg rests on a rough horizontal plane. The plane is gradually inclined. When the angle becomes 15° , the block just begins to slide. Find the coefficient of static friction (μₛ) . Given Data Mass of block, m = 4 kg Angle of inclination, θ = 15° Find μₛ Step 1: Understand the Situation As the plane is tilted, the component of weight ac...