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Friday, July 24, 2026

Power Class 11 Physics Notes for NEET | Complete Revision Guide

 - Dr.Sanjaykumar Pawar  

Power Physics Notes PDF | NEET Work, Energy and Power Chapter

Illustration explaining Power in Physics for NEET students including average power, instantaneous power, formulas, SI units, horsepower, kilowatt-hour, examples and important revision notes.
Power in Physics – Complete NEET Notes with Formulas, Units, Examples and Quick Revision


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CBSE Class 11 Physics — Power: Complete Question Bank

Work, Energy and Power · Unit IV

Power — Complete Question Bank

A full CBSE Class 11 Physics practice set on Power: MCQs, assertion–reason, case studies, match-the-columns, numericals, and a quick answer key — click any answer to reveal it.

Class 11 · CBSE Chapter: Work, Energy & Power 100+ Questions Answer Key Included

Section A Multiple Choice Questions

Tap "Show Answer" under any question to reveal the solution.

Level · Easy

Q1.Power is defined as:

Easy
  • (a) Total work done
  • (b) Rate of doing work
  • (c) Energy stored in a body
  • (d) Force applied per unit area
Show Answer
Answer: (b) Rate of doing work

Q2.The SI unit of power is:

Easy
  • (a) Joule
  • (b) Newton
  • (c) Watt
  • (d) Pascal
Show Answer
Answer: (c) Watt

Q3.1 horsepower is equal to:

Easy
  • (a) 500 W
  • (b) 746 W
  • (c) 1000 W
  • (d) 980 W
Show Answer
Answer: (b) 746 W

Q4.A machine does 1000 J of work in 10 s. Its power is:

Easy
  • (a) 10 W
  • (b) 100 W
  • (c) 1000 W
  • (d) 10000 W
Show Answer
Answer: (b) 100 W

Q5.The dimensional formula of power is:

Easy
  • (a) [ML²T⁻²]
  • (b) [ML²T⁻³]
  • (c) [MLT⁻²]
  • (d) [M²L²T⁻²]
Show Answer
Answer: (b) [ML²T⁻³]

Q6.Power is a:

Easy
  • (a) Vector quantity
  • (b) Scalar quantity
  • (c) Neither scalar nor vector
  • (d) Tensor quantity
Show Answer
Answer: (b) Scalar quantity

Q7.A pump lifts 200 kg of water to a height of 5 m in 10 s (g = 10 m/s²). The power of the pump is:

Easy
  • (a) 100 W
  • (b) 500 W
  • (c) 1000 W
  • (d) 2000 W
Show Answer
Answer: (c) 1000 W

Q8.If force and velocity are perpendicular to each other, the power is:

Easy
  • (a) Maximum
  • (b) Minimum
  • (c) Zero
  • (d) Infinite
Show Answer
Answer: (c) Zero

Level · Medium

Q9.A car engine exerts a force of 500 N while moving at a constant speed of 20 m/s. The power of the engine in hp is approximately:

Medium
  • (a) 10.7 hp
  • (b) 13.4 hp
  • (c) 15.2 hp
  • (d) 20.0 hp
Show Answer
Answer: (b) 13.4 hpP = Fv = 500 × 20 = 10000 W = 10000/746 ≈ 13.4 hp

Q10.The position of a particle is given by x = 3t² + 2t (x in m, t in s). A force of 6 N acts on it. The power at t = 2 s is:

Medium
  • (a) 72 W
  • (b) 84 W
  • (c) 96 W
  • (d) 108 W
Show Answer
Answer: (b) 84 Wv = dx/dt = 6t + 2. At t = 2s, v = 14 m/s. P = Fv = 6 × 14 = 84 W

Q11.A body of mass 2 kg is moved by a force of 10 N at constant velocity of 5 m/s at 60° to the direction of force. The power is:

Medium
  • (a) 50 W
  • (b) 25 W
  • (c) 43.3 W
  • (d) 0 W
Show Answer
Answer: (b) 25 WP = Fv cosθ = 10 × 5 × cos60° = 50 × 0.5 = 25 W

Q12.An engine of power 2 kW can do how much work in 1 minute?

Medium
  • (a) 120 J
  • (b) 2000 J
  • (c) 120000 J
  • (d) 20000 J
Show Answer
Answer: (c) 120000 JW = P × t = 2000 × 60 = 120000 J

Q13.A force F acts on a body moving with velocity v. If the angle between F and v is 120°, the power is:

Medium
  • (a) Fv
  • (b) Fv/2
  • (c) Zero
  • (d) −Fv/2
Show Answer
Answer: (d) −Fv/2P = Fv cos120° = Fv × (−1/2) = −Fv/2

Q14.The power of a pump that can lift 5000 kg of water per minute to a height of 20 m is: (g = 10 m/s²)

Medium
  • (a) 16.67 kW
  • (b) 10 kW
  • (c) 100 kW
  • (d) 1.67 kW
Show Answer
Answer: (a) 16.67 kWP = mgh/t = (5000 × 10 × 20)/60 = 1,000,000/60 ≈ 16,667 W ≈ 16.67 kW

Q15.A man of mass 60 kg climbs up a staircase carrying a load of 20 kg. If the total height gained is 10 m in 20 s, the average power is: (g = 10 m/s²)

Medium
  • (a) 200 W
  • (b) 300 W
  • (c) 400 W
  • (d) 800 W
Show Answer
Answer: (c) 400 WTotal mass = 80 kg. P = mgh/t = (80 × 10 × 10)/20 = 400 W

Level · Hard

Q16.A particle of mass m moves along a circular path of radius r with uniform speed v. The power delivered by the centripetal force is:

Hard
  • (a) mv²/r
  • (b) mv³/r
  • (c) Zero
  • (d) mv²r
Show Answer
Answer: (c) ZeroCentripetal force is always perpendicular to velocity (θ = 90°), so P = Fv cos90° = 0

Q17.The power delivered to a body moving in a straight line is given by P = 3t² + 2t (in watts). The work done in the first 2 seconds is:

Hard
  • (a) 10 J
  • (b) 12 J
  • (c) 14 J
  • (d) 16 J
Show Answer
Answer: (d) 16 JW = ∫P dt = ∫(3t² + 2t)dt = t³ + t². At t = 2: W = 8 + 8 = 16 J

Q18.A body of mass 1 kg is thrown vertically upward with initial velocity 20 m/s. The instantaneous power due to gravity at t = 1 s is: (g = 10 m/s²)

Hard
  • (a) 100 W
  • (b) −100 W
  • (c) 200 W
  • (d) −200 W
Show Answer
Answer: (b) −100 Wv = u − gt = 20 − 10 = 10 m/s (upward). F = mg = 10 N (downward). P = Fv cos180° = 10 × 10 × (−1) = −100 W

Q19.A pump motor is rated at 5 hp. How many kilograms of water can it raise in 1 minute through a height of 10 m? (g = 10 m/s², 1 hp = 746 W)

Hard
  • (a) 1492 kg
  • (b) 2238 kg
  • (c) 2984 kg
  • (d) 3730 kg
Show Answer
Answer: (b) 2238 kgP = 5 × 746 = 3730 W. W = P × t = 3730 × 60 = 223,800 J. m = W/(gh) = 223,800/(10×10) = 2238 kg

Q20.A vehicle of mass m accelerates uniformly from rest to velocity v in time t. The instantaneous power delivered by the engine at time t/2 is:

Hard
  • (a) mv²/2t
  • (b) mv²/4t
  • (c) mv²/t
  • (d) 3mv²/4t
Show Answer
Answer: (a) mv²/2ta = v/t (constant). At t/2, instantaneous velocity v′ = a(t/2) = v/2. F = ma = mv/t. P = F·v′ = (mv/t)(v/2) = mv²/2t.

Section B Very Short Answer Questions (1 Mark Each)

Q1.Define power.

Show Answer
Power is defined as the rate of doing work or the rate of energy transfer. Mathematically, P = W/t

Q2.Write the SI unit of power.

Show Answer
Watt (W), where 1 W = 1 J/s.

Q3.What is 1 horsepower in watts?

Show Answer
1 hp = 746 W.

Q4.Is power a scalar or vector quantity? Why?

Show Answer
Power is a scalar quantity because it has only magnitude and no direction. It is the ratio of two scalars (work and time).

Q5.Write the dimensional formula of power.

Show Answer
[M¹L²T⁻³]

Q6.A force acts perpendicular to the velocity of a body. What is the power?

Show Answer
Zero, because P = Fv cos90° = 0.

Q7.What is the relation between power, force, and velocity?

Show Answer
P = Fv (when force and velocity are in the same direction).

Q8.A machine does no work. Can it have power?

Show Answer
No. Since P = W/t, if W = 0, then P = 0.

Q9.What is the commercial unit of power?

Show Answer
Horsepower (hp).

Q10.Write the expression for instantaneous power.

Show Answer
P = dW/dt or P = F·v (dot product of force and instantaneous velocity).

Section C Short Answer Questions (2 Marks Each)

Q1.Distinguish between average power and instantaneous power.

Show Answer
Average PowerInstantaneous Power
Defined as total work divided by total timeDefined as power at a particular instant
Formula: Pavg = W/tFormula: Pinst = F·v
Used when total work and time are givenUsed when force or velocity varies with time

Q2.Derive the relation P = Fv.

Show Answer
We know power P = W/t. Work done W = F × s (for constant force in direction of displacement). Therefore, P = (F × s)/t = F × (s/t) = F × v. Hence, P = Fv

Q3.A pump delivers 1000 liters of water per minute to a tank at a height of 20 m. Find the power of the pump. (Density of water = 1000 kg/m³, g = 10 m/s²)

Show Answer
Volume per second = 1000/60 = 50/3 L/s = (50/3) × 10⁻³ m³/s. Mass per second = ρ × volume/s = 1000 × (50/3) × 10⁻³ = 50/3 kg/s. Power = (m/t) × gh = (50/3) × 10 × 20 = 10000/3 ≈ 3333.33 W ≈ 3.33 kW

Q4.Show that the power delivered by the centripetal force in uniform circular motion is zero.

Show Answer
In uniform circular motion, the centripetal force is always directed towards the center, while the velocity is always tangential. So θ = 90° always. P = Fv cosθ = Fv cos90° = 0.

Q5.The power of an engine is 5 kW. How much work can it do in 10 minutes?

Show Answer
Given: P = 5 kW = 5000 W, t = 10 min = 600 s. W = P × t = 5000 × 600 = 3,000,000 J = 3 × 10⁶ J

Q6.A car of mass 1000 kg moves up an incline of 1 in 20 at a constant speed of 10 m/s. Find the power of the engine. (g = 10 m/s², neglect friction)

Show Answer
Slope = 1/20, so sinθ = 1/20. Force required F = mg sinθ = 1000 × 10 × (1/20) = 500 N. Power P = Fv = 500 × 10 = 5000 W = 5 kW

Q7.Why is the power of a body moving with constant velocity on a frictionless horizontal surface zero?

Show Answer
On a frictionless horizontal surface, no external force is required to maintain constant velocity (Newton's first law). Since F = 0, power P = Fv = 0 × v = 0.

Q8.A 2 kW motor pump is used to pump water from a well 10 m deep. How much water can be pumped per minute? (g = 10 m/s²)

Show Answer
P = 2 kW = 2000 W, t = 60 s. W = P × t = 2000 × 60 = 120,000 J. m = W/(gh) = 120,000/(10 × 10) = 1200 kg

Section D Long Answer Questions (3–5 Marks Each)

Q1.(a) Define power and derive its SI unit. (2 marks)
(b) A pump can throw 8000 kg of water per minute to a height of 15 m. Calculate the power of the pump. (g = 9.8 m/s²) (3 marks)

Show Answer
(a) Power is defined as the rate of doing work. If W is the work done in time t, then P = W/t. The SI unit of work is Joule (J) and time is second (s). Therefore, SI unit of power = J/s = Watt (W). 1 Watt = 1 Joule per second.

(b) Given: m = 8000 kg (per minute), h = 15 m, t = 60 s, g = 9.8 m/s². Work done per minute = mgh = 8000 × 9.8 × 15 = 1,176,000 J. Power P = W/t = 1,176,000/60 = 19,600 W = 19.6 kW

Q2.(a) Derive the expression for instantaneous power. (2 marks)
(b) The position of a body of mass 2 kg is given by x = 2t³ + 3t² + 5, where x is in meters and t in seconds. A constant force of 12 N acts on the body in the direction of motion. Calculate the power delivered at t = 2 s. (3 marks)

Show Answer
(a) Consider a small amount of work dW done in a small time interval dt. Instantaneous power P = dW/dt. Since dW = F·ds, we get P = (F·ds)/dt = F·(ds/dt) = F·v. Therefore, P = F·v (dot product of force and instantaneous velocity).

(b) x = 2t³ + 3t² + 5 → v = dx/dt = 6t² + 6t. At t = 2 s: v = 6(4) + 6(2) = 24 + 12 = 36 m/s. Power P = F × v = 12 × 36 = 432 W

Q3.(a) Prove that power can also be expressed as the scalar product of force and velocity. (2 marks)
(b) An engine of power 10 hp is used to pump water from a well 8 m deep. How many kilograms of water can be pumped in 1 hour? (1 hp = 746 W, g = 9.8 m/s²) (3 marks)

Show Answer
(a) Work done by a force F in displacing a body by ds is dW = F·ds. Power is rate of doing work: P = dW/dt = (F·ds)/dt = F·(ds/dt) = F·v. Hence, P = F·v.

(b) P = 10 hp = 10 × 746 = 7460 W. t = 1 hour = 3600 s. Total work W = P × t = 7460 × 3600 = 26,856,000 J. m = W/(gh) = 26,856,000/(9.8 × 8) = 26,856,000/78.4 ≈ 342,551 kg

Q4.(a) What is the difference between kilowatt and kilowatt-hour? (2 marks)
(b) A family uses a 2 kW electric heater for 4 hours daily. Calculate the energy consumed in 30 days in kWh and joules. (3 marks)

Show Answer
(a)
Kilowatt (kW)Kilowatt-hour (kWh)
Unit of powerUnit of energy
1 kW = 1000 W1 kWh = 1000 W × 3600 s = 3.6 × 10⁶ J
Measures rate of energy consumptionMeasures total energy consumed

(b) Power P = 2 kW, daily usage t = 4 h. Daily energy = 2 × 4 = 8 kWh. 30-day energy = 8 × 30 = 240 kWh. In joules: 240 kWh = 240 × 3.6 × 10⁶ = 8.64 × 10⁸ J

Section E Assertion and Reason Questions

Choose: (a) Both true, Reason correctly explains Assertion  |  (b) Both true, Reason does NOT explain Assertion  |  (c) Assertion true, Reason false  |  (d) Assertion false, Reason true

Q1.Assertion: Power is a scalar quantity.
Reason: Power is the ratio of two scalar quantities, work and time.

Show Answer
Answer: (a) Both true and Reason correctly explains Assertion.

Q2.Assertion: When a body moves in a circular path with uniform speed, the power delivered by the centripetal force is zero.
Reason: The centripetal force is always perpendicular to the velocity of the body.

Show Answer
Answer: (a) Both true and Reason correctly explains Assertion.

Q3.Assertion: A body moving with constant velocity on a frictionless horizontal surface has zero power.
Reason: No force is required to maintain constant velocity on a frictionless surface.

Show Answer
Answer: (a) Both true and Reason correctly explains Assertion.

Q4.Assertion: 1 horsepower is equal to 1000 watts.
Reason: Horsepower is the commercial unit of power.

Show Answer
Answer: (c) Assertion is false but Reason is true. (1 hp = 746 W, not 1000 W)

Q5.Assertion: The instantaneous power of a body can be negative.
Reason: Power is always positive because it is the rate of doing work.

Show Answer
Answer: (c) Assertion is true but Reason is false. (Power can be negative when force opposes motion, e.g., friction doing negative work)

Q6.Assertion: Average power is always equal to instantaneous power.
Reason: Average power is calculated over a time interval while instantaneous power is at a specific instant.

Show Answer
Answer: (d) Assertion is false but Reason is true.

Q7.Assertion: The power delivered by gravity to a body thrown vertically upward is negative.
Reason: The gravitational force acts opposite to the direction of motion during upward journey.

Show Answer
Answer: (a) Both true and Reason correctly explains Assertion.

Q8.Assertion: A pump requires more power to lift the same amount of water to a greater height.
Reason: Power is directly proportional to the height through which water is lifted.

Show Answer
Answer: (a) Both true and Reason correctly explains Assertion.

Section F Fill in the Blanks

Q1.Power is defined as the ______ of doing work.

Show Answer
rate

Q2.The SI unit of power is ______, named after the scientist ______.

Show Answer
Watt, James Watt

Q3.1 horsepower = ______ watts.

Show Answer
746

Q4.The dimensional formula of power is ______.

Show Answer
[M¹L²T⁻³]

Q5.When force and velocity are perpendicular to each other, the power is ______.

Show Answer
zero

Q6.The commercial unit of power is ______.

Show Answer
horsepower (hp)

Q7.For a body moving with constant velocity on a frictionless surface, the power is ______.

Show Answer
zero

Q8.Instantaneous power is given by the scalar product of ______ and ______.

Show Answer
force, velocity

Q9.1 kilowatt = ______ watts.

Show Answer
1000

Q10.The power of a pump lifting mass m through height h in time t is given by P = ______.

Show Answer
mgh/t

Section G Case Study Based Questions

Case Study 1 · Hydroelectric Power Plant

A hydroelectric power plant uses water falling from a height to generate electricity. Water from a reservoir at a height of 100 m flows down through penstocks to turn turbines. The plant has a capacity to process 5000 kg of water per second. (Take g = 10 m/s²)

Q1.What is the power generated by the falling water?

Show Answer
P = mgh/t = (5000 × 10 × 100)/1 = 5,000,000 W = 5 MW

Q2.If the efficiency of the turbine-generator system is 80%, what is the actual electrical power output?

Show Answer
Actual power = 80% of 5 MW = 0.8 × 5 = 4 MW

Q3.How much energy is produced in 1 hour at this actual power output?

Show Answer
E = P × t = 4 MW × 1 h = 4 MWh = 4 × 10⁶ Wh = 1.44 × 10¹⁰ J

Case Study 2 · Electric Vehicle

An electric car of mass 1500 kg accelerates from rest to a speed of 30 m/s in 10 seconds. The motor delivers constant power during this time.

Q1.What is the acceleration of the car?

Show Answer
a = (v − u)/t = (30 − 0)/10 = 3 m/s²

Q2.What is the average power delivered by the motor during acceleration?

Show Answer
Work done = ΔKE = ½mv² = ½ × 1500 × 30² = 675,000 J. Pavg = W/t = 675,000/10 = 67,500 W = 67.5 kW

Q3.If the car maintains a constant speed of 30 m/s on a level road with a frictional force of 500 N, what power is required to overcome friction?

Show Answer
P = Fv = 500 × 30 = 15,000 W = 15 kW

Case Study 3 · Human Power Output

A person of mass 70 kg climbs a staircase of 50 steps, each 20 cm high, in 20 seconds. (g = 9.8 m/s²)

Q1.What is the total height climbed?

Show Answer
h = 50 × 0.20 = 10 m

Q2.What is the work done against gravity?

Show Answer
W = mgh = 70 × 9.8 × 10 = 6860 J

Q3.What is the average power output of the person?

Show Answer
P = W/t = 6860/20 = 343 W

Section H Statement Based Questions

Passage 1

"Power is the rate at which work is done. It is a scalar quantity. The SI unit of power is watt. When a force acts on a body in the direction of its motion, the power is given by P = Fv. If the force makes an angle θ with the velocity, then P = Fv cosθ."

Q1.Why is power called a scalar quantity?

Show Answer
Power is a scalar quantity because it has only magnitude and no direction. It is derived as the ratio of work (scalar) and time (scalar), and the dot product of two vectors (F·v) also yields a scalar.

Q2.A force of 20 N acts on a body moving with a velocity of 4 m/s. The force makes an angle of 60° with the direction of motion. Calculate the power.

Show Answer
P = Fv cosθ = 20 × 4 × cos60° = 80 × 0.5 = 40 W

Passage 2

"A pump is used to lift water from a well. The power of the pump depends on the mass of water lifted, the height to which it is lifted, and the time taken. The efficiency of the pump is defined as the ratio of useful power output to the total power input."

Q1.Write the expression for the power of a pump lifting water.

Show Answer
P = mgh/t

Q2.A pump of power 2 kW and efficiency 75% is used to lift water through 10 m. How much water can it lift in 1 minute? (g = 10 m/s²)

Show Answer
Useful power = 75% of 2 kW = 0.75 × 2000 = 1500 W. Work done in 1 min = 1500 × 60 = 90,000 J. m = W/(gh) = 90,000/(10 × 10) = 900 kg

Section I Match the Columns

Match the Following 1
Column AColumn B
(a) Unit of power(p) [M¹L²T⁻³]
(b) Dimensional formula of power(q) Joule
(c) Unit of work(r) Watt
(d) 1 hp(s) 746 W
Show Answer
(a) → (r)  |  (b) → (p)  |  (c) → (q)  |  (d) → (s)
Match the Following 2
Column A (Physical Quantity)Column B (Expression)
(a) Average power(p) F·v
(b) Instantaneous power(q) W/t
(c) Power in lifting(r) mgh/t
(d) Power when F ⊥ v(s) Zero
Show Answer
(a) → (q)  |  (b) → (p)  |  (c) → (r)  |  (d) → (s)
Match the Following 3
Column A (Situation)Column B (Power)
(a) Body moving with constant velocity on frictionless surface(p) Positive
(b) Body thrown upward against gravity(q) Negative
(c) Body falling freely under gravity(r) Zero
(d) Body in uniform circular motion(s) Variable
Show Answer
(a) → (r) Zero, as F = 0  |  (b) → (q) Negative, gravity opposes motion  |  (c) → (p) Positive, gravity aids motion  |  (d) → (r) Zero, centripetal force ⊥ velocity
Match the Following 4
Column AColumn B
(a) James Watt(p) Unit of energy
(b) Joule(q) Commercial unit of power
(c) Horsepower(r) SI unit of power
(d) Kilowatt-hour(s) Improved steam engine
Show Answer
(a) → (s)  |  (b) → (p)  |  (c) → (q)  |  (d) → (p) — kWh is a unit of energy, like Joule
Match the Following 5
Column A (Value)Column B (Equivalent)
(a) 1 kW(p) 3.6 × 10⁶ J
(b) 1 kWh(q) 1000 W
(c) 1 hp(r) 746 W
(d) 1 W(s) 1 J/s
Show Answer
(a) → (q)  |  (b) → (p)  |  (c) → (r)  |  (d) → (s)

Section J True or False

Q1.Power and work have the same dimensions.

Show Answer
False. [Work] = [ML²T⁻²], [Power] = [ML²T⁻³]

Q2.1 kilowatt-hour is a unit of power.

Show Answer
False. It is a unit of energy.

Q3.The power of a body can be negative.

Show Answer
True. When force opposes motion (e.g., friction), power is negative.

Q4.A body in uniform circular motion has zero power due to centripetal force.

Show Answer
True. Centripetal force is perpendicular to velocity.

Q5.The SI unit of power is named after James Prescott Joule.

Show Answer
False. It is named after James Watt.

Section K Numerical Problems (With Detailed Solutions)

Q1.A pump lifts 1200 kg of water per minute to a height of 25 m. Calculate the power of the pump in kW. (g = 10 m/s²)

Show Solution
m = 1200 kg, h = 25 m, t = 60 s, g = 10 m/s². P = mgh/t = (1200 × 10 × 25)/60 = 300,000/60 = 5000 W = 5 kW

Q2.A car of mass 1000 kg moves on a level road at a constant speed of 20 m/s against a resistance of 400 N. Find the power of the engine in horsepower.

Show Solution
At constant speed, engine force = resistance = 400 N. P = Fv = 400 × 20 = 8000 W. In hp: 8000/746 ≈ 10.7 hp

Q3.The power of an engine is 5 kW. How much time will it take to lift a load of 500 kg to a height of 40 m? (g = 10 m/s²)

Show Solution
W = mgh = 500 × 10 × 40 = 200,000 J. P = 5000 W. t = W/P = 200,000/5000 = 40 s

Q4.A force F = (3i + 4j) N acts on a body moving with velocity v = (4i − 3j) m/s. Calculate the power.

Show Solution
P = F·v = (3)(4) + (4)(−3) = 12 − 12 = 0 W

Q5.A motor pump is rated at 3 hp. Calculate the maximum mass of water it can lift in 2 minutes through a height of 15 m. (1 hp = 746 W, g = 9.8 m/s²)

Show Solution
P = 3 × 746 = 2238 W. t = 120 s. W = P × t = 2238 × 120 = 268,560 J. m = W/(gh) = 268,560/(9.8 × 15) = 268,560/147 ≈ 1827 kg

Answer Key (Quick Reference — MCQs & Assertion-Reason)

SectionQ. No.Answer
MCQ (Easy)1(b)
2(c)
3(b)
4(b)
5(b)
6(b)
7(c)
8(c)
MCQ (Medium)9(b)
10(b)
11(b)
12(c)
13(d)
14(a)
15(c)
MCQ (Hard)16(c)
17(d)
18(b)
19(b)
20(a)
Assertion-Reason1(a)
2(a)
3(a)
4(c)
5(c)
6(d)
7(a)
8(a)

Exam Tips for CBSE Class 11

  1. Formula Sheet: Memorize P = W/t, P = Fv, P = Fv cosθ, and P = mgh/t
  2. Unit Conversions: Always convert to SI units first (especially hp → W, min → s)
  3. Sign Convention: Power is positive when force aids motion, negative when it opposes
  4. Scalar Nature: Remember power is scalar — never add vectorially
  5. Time Management: Most Power questions take 1–2 minutes max
Best of luck for your CBSE Class 11 exams — master these questions and you're set for full marks on Power. 🎓
NEET Physics Notes - Power

NEET Physics Notes
Chapter: POWER

Definition:
Power is the rate at which work is done or energy is transferred.

Simple Meaning

Work tells us how much work is done, while Power tells us how fast the work is done.

Example

  • Student A climbs 4 floors in 20 seconds.
  • Student B climbs 4 floors in 40 seconds.

Both students do the same work, but Student A has more power because he completes the work in less time.

Average Power

P = W / t

Where

  • P = Average Power (Watt)
  • W = Work Done (Joule)
  • t = Time Taken (Second)
More Work + Less Time = More Power

Instantaneous Power

The power at a particular instant of time is called Instantaneous Power.

P = dW / dt

Power in Terms of Force

We know

dW = F · dr

Therefore

P = dW / dt

Since

dr / dt = v

Hence

P = F · v

General Formula

P = Fv cosθ

Special Cases

Case 1: Force and Velocity in Same Direction

θ = 0°

P = Fv

Power is Maximum.


Case 2: Force Opposite to Velocity

θ = 180°

P = -Fv

Negative power means energy is removed from the body.

Example: Braking a moving car.


Case 3: Force Perpendicular to Velocity

θ = 90°

P = 0

Example: Uniform Circular Motion

The centripetal force changes only the direction of velocity, not its speed.

Nature of Power

Power is a Scalar Quantity.

Reason: It is obtained from the dot product of force and velocity.

Dimensions of Power

[ML²T⁻³]

SI Unit

Watt (W)

Named after James Watt, who improved the steam engine.

Definition of One Watt

1 Watt = 1 Joule / Second

A power of one watt means one joule of work is done every second.

Other Units

1 kW = 1000 W
1 hp = 746 W

Horsepower is commonly used for engines, cars and motorcycles.

Electrical Energy

Electrical appliances are rated in watts.

  • 60 W Bulb
  • 100 W Bulb
  • 1000 W Heater

Higher wattage means the appliance consumes energy faster.

Kilowatt-hour (kWh)

Electricity bills are measured in kilowatt-hour (kWh).

Energy = Power × Time

Conversion

1 kWh = 1000 W × 3600 s

= 3.6 × 10⁶ J

Example

A 100 W bulb runs for 10 hours.

100 × 10 = 1000 Wh

= 1 kWh
A 100 W bulb used for 10 hours consumes 1 Unit of electricity.

Important Fact

1 Unit of Electricity = 1 kWh = 3.6 × 10⁶ Joules

Remember:
kWh is a unit of Energy, NOT Power.

Difference Between Power and Energy

Power Energy
Rate of doing work Capacity to do work
P = W / t W = Pt
Unit = Watt (W) Unit = Joule (J)
Scalar Quantity Scalar Quantity
Measures speed of work Measures amount of work

Graph Concept

Slope of Work-Time Graph = Power

NEET Formula Sheet

Formula Expression
Average Power P = W / t
Instantaneous Power P = dW / dt
Power by Force P = F · v
General Formula P = Fv cosθ
Parallel Force P = Fv
Perpendicular Force P = 0
Opposite Force P = -Fv
1 Watt 1 J/s
Horsepower 1 hp = 746 W
1 kWh 3.6 × 10⁶ J

NEET Quick Revision

  • Power = Rate of doing work.
  • Power = Speed of energy transfer.
  • Power is a scalar quantity.
  • P = Fv cosθ.
  • Maximum power when θ = 0°.
  • Zero power when θ = 90°.
  • Negative power when θ = 180°.
  • 1 Watt = 1 Joule/second.
  • 1 Horsepower = 746 W.
  • 1 Unit of electricity = 1 kWh = 3.6 × 10⁶ J.
  • kWh is a unit of Energy, not Power.

Frequently Asked NEET Questions

Q1. What is Power?

Power is the rate at which work is done or energy is transferred.

Q2. Why is Power a Scalar Quantity?

Because Power is obtained from the dot product of Force and Velocity.

Q3. What is SI Unit of Power?

Watt (W).

Q4. Is kWh a unit of Power?

No. It is a unit of Energy.

Q5. What is the power when Force is perpendicular to Velocity?

P = 0

Saturday, July 18, 2026

NEET Physics: Motion in One Dimension – Mechanics, Kinematics & Dynamics Notes

 

NEET Physics – Motion in One Dimension

Infographic explaining Motion in One Dimension, Mechanics, Kinematics, Dynamics, Frame of Reference, and Point Object concepts for NEET Physics students.
Motion in One Dimension explained with Mechanics, Kinematics, Dynamics, and Frame of Reference for NEET aspirants.


Chapter 1: Basic Concepts of Mechanics (Complete Notes)

-Dr.Sanjaykumar Pawar 

1. What is Physics?

Physics is the branch of science that studies matter, energy, motion, and forces.

Example:

  • Why does a ball fall?

  • Why does a bike move?

  • Why do planets revolve around the Sun?

All these are studied in Physics.


2. What is Mechanics?

Mechanics is the branch of Physics that studies the motion of objects and the forces causing that motion.

Simple Definition

Mechanics = Study of motion + causes of motion.


Mechanics is divided into two parts

              Mechanics
             /          \
      Kinematics      Dynamics

3. Kinematics

Definition

Kinematics is the branch of mechanics that studies motion without considering the force causing it.

It tells us

  • Where the object is

  • How fast it moves

  • How far it moves

  • How long it takes

But NOT why it moves.

Example

A car moves with speed 40 km/h.

Kinematics studies

✔ Speed

✔ Distance

✔ Time

✔ Displacement

It does NOT study engine force.


4. Dynamics

Definition

Dynamics studies motion along with the forces responsible for the motion.

It answers

Why does the object move?

Example

A football moves because a player kicks it.

Dynamics studies the force of the kick.


Difference Between Kinematics and Dynamics

KinematicsDynamics
Studies motion onlyStudies motion + force
Force is ignoredForce is considered
Easier chapterUses Newton's Laws
Example: SpeedExample: Force

5. Frame of Reference

This is one of the most important concepts in NEET.

Definition

A Frame of Reference is a coordinate system attached to an observer from which measurements of position and time are made.

Simply,

It is the point from which an observer watches motion.


It contains

(1) Observer

Who is watching?

Example

You

Driver

Passenger

Teacher


(2) Space Coordinate

Where is the object?

Usually represented by

x-axis

y-axis

z-axis


(3) Time Coordinate

When is the object observed?

Measured using a clock.


Example

A train is moving.

Passenger says

"I am at rest."

A person standing on the platform says

"The train is moving."

Both are correct because their frames of reference are different.


Important Points

Motion depends on

✔ Observer

✔ Position

✔ Time


There is NO Absolute Motion

Motion is always relative.

There is nothing called

❌ Absolute Motion

❌ Absolute Rest

Everything depends upon the observer.


Example

You are sitting inside a moving bus.

With respect to

Seat → You are at rest.

Road → You are moving.

Both answers are correct.


6. Rest and Motion

Rest

An object is at rest if its position does not change with respect to the observer.

Example

Book lying on a table.


Motion

An object is in motion if its position changes with time with respect to an observer.

Example

Running car.

Flying bird.

Moving train.


Remember

Motion requires

✔ Observer

✔ Position

✔ Time


7. Point Object (Particle)

Very important for NEET.

Definition

A point object is an object whose size is very small compared to the distance travelled, so its dimensions can be ignored.


Example

Bike length = 2 m

Distance travelled = 500 km

Compared to 500 km,

2 m is negligible.

So bike is treated as a point object.


Another Example

Earth revolves around the Sun.

Earth diameter = 12,742 km

Distance from Sun = 150 million km

Compared to this huge distance,

Earth behaves like a point object.


When can an object be treated as a Point Object?

Ignore size when

Distance travelled ≫ Size of object


Example

ObjectDistancePoint Object?
Car travelling 200 kmYes
Cricket ball moving 40 mYes
Pencil moving 2 cmNo

8. Position

Position tells where an object is located with respect to a chosen origin.

Example

If a boy stands 5 m to the right of the origin,

Position = +5 m

If he stands 3 m to the left,

Position = −3 m


9. Origin

Origin is the reference point from which distances are measured.

Usually represented by

O

Example

<------|------|------|------>

     -2    -1    O    +1   +2

10. Coordinate System

Used to locate objects.

One-dimensional (1D)

Only x-axis

Example

Train on straight track.


Two-dimensional (2D)

x-axis and y-axis

Example

Football ground.


Three-dimensional (3D)

x-axis

y-axis

z-axis

Example

Flying aeroplane.


Important NEET Concepts

Observer

Person who measures motion.


Coordinate

Shows position.


Time

Shows when motion occurs.


Motion depends on observer.

Always remember

Motion is Relative.


Frequently Asked NEET Facts

SI Unit of Distance

metre (m)


SI Unit of Time

second (s)


SI Unit of Speed

m/s


SI Unit of Force

Newton (N)


Previous Year NEET Concepts

Example 1

A passenger sitting inside a moving train is

A) Moving with respect to train

B) At rest with respect to train

C) Moving with respect to seat

D) None

Answer

B


Example 2

A car moves from Delhi to Jaipur.

The car is treated as

A) Rigid body

B) Point object

C) Fluid

D) None

Answer

B


Example 3

Motion is

A) Absolute

B) Relative

C) Constant

D) None

Answer

B


Formula Sheet (This Topic)

There are no numerical formulas in this introductory topic. Focus on understanding the concepts.


One-Page Revision

Mechanics

  • Study of motion and the causes of motion.

Kinematics

  • Motion only.

  • No force.

Dynamics

  • Motion + force.

Frame of Reference

  • Observer + coordinate system + time.

Motion

  • Position changes with time relative to an observer.

Rest

  • Position does not change relative to an observer.

Point Object

  • Size is negligible compared to the distance travelled.

Key Rule

  • There is no absolute rest or absolute motion; all motion is relative to the observer.

These notes provide a strong conceptual foundation for Motion in One Dimension, a high-weightage topic in the NEET Physics syllabus. 


Internal Links

  1. Units and Measurements Notes for NEET
  2. Vector and Scalar Quantities
  3. Motion in Two Dimensions
  4. Laws of Motion
  5. Work, Energy and Power
  6. System of Particles and Rotational Motion
  7. Gravitation Notes
  8. Oscillations and SHM
  9. Mechanical Properties of Solids
  10. Mechanical Properties of Fluids
  11. Thermal Physics Complete Notes
  12. Waves and Sound Notes
  13. Complete NEET Physics Formula Sheet
  14. NEET Physics PYQs Chapter-wise
  15. Motion in One Dimension MCQs with Answers
  16. Motion in One Dimension Numericals for NEET 
  17. Motion in One Dimension Revision Notes
  18. Class 11 Physics Complete Notes
  19. NEET Physics Mock Tests
  20. NEET Physics Study Plan
NEET Physics - Motion in One Dimension | Part 1

🔥 NEET Physics – Motion in One Dimension

Part 1 : Ultra-Hard NEET Numericals

Instructions

  • Total Questions : 25
  • Difficulty : NEET Advanced
  • Use SI Units.
  • Take g = 10 m/s² whenever required.
  • Do not use calculator unless instructed.

Q1.

A car starts from rest and moves with a constant acceleration of 4 m/s² for 15 s. Calculate
  1. Final velocity
  2. Total displacement
  3. Average velocity

Q2.

A train moving at 20 m/s accelerates uniformly to 50 m/s in 15 s. Find
  1. Acceleration
  2. Distance travelled

Q3.

A body travels
  • 40 m East
  • 30 m West
  • 20 m East
Calculate
  1. Total distance
  2. Displacement

Q4.

A particle moves with velocity v = 5 + 2t where t is in seconds. Find
  1. Velocity after 8 s
  2. Displacement in first 8 s

Q5.

A ball is thrown vertically upward with speed 40 m/s. Calculate
  1. Maximum height
  2. Time to reach highest point
  3. Total time of flight

Q6.

A runner completes
  • First half distance at 10 m/s
  • Second half distance at 15 m/s
Find average speed.

Q7.

A particle covers
  • 100 m in North direction
  • 100 m in East direction
Calculate
  1. Distance
  2. Displacement

Q8.

A car moving at 25 m/s stops uniformly in 5 seconds. Calculate
  1. Retardation
  2. Stopping distance

Q9.

Two cars move towards each other. Car A = 30 m/s Car B = 20 m/s Initially separated by 500 m. Find time to meet.

Q10.

A particle travels
  • 2 hours at 40 km/h
  • 3 hours at 60 km/h
Find
  1. Total distance
  2. Average speed

Q11.

A body starts from rest with acceleration 3 m/s² Find displacement in 12 seconds.

Q12.

A train moving at 72 km/h crosses a 300 m platform in 30 s. Find length of train.

Q13.

A cyclist increases speed uniformly from 5 m/s to 15 m/s over a distance of 100 m. Find acceleration.

Q14.

A body moves 10 m East 10 m North 10 m West Find displacement.

Q15.

A particle has velocity v = 20 − 5t Find
  1. Time when particle stops
  2. Distance travelled till then

Q16.

A stone falls freely from a tower. It reaches ground in 6 s. Find
  1. Height of tower
  2. Velocity on reaching ground

Q17.

A bus travels 80 km at 40 km/h and 120 km at 60 km/h. Find average speed.

Q18.

A particle moves according to s = 4t² + 3t Find velocity after 5 seconds.

Q19.

Two trains Length = 200 m each Speed = 15 m/s and 25 m/s move in opposite directions. Find time taken to cross each other.

Q20.

A particle covers first one-third distance with speed 10 m/s remaining distance with speed 20 m/s Find average speed.

Q21.

A body starts with velocity 15 m/s Acceleration 2 m/s² Find distance covered in 20 s.

Q22.

A particle moves 50 m East 120 m West 70 m East Calculate displacement.

Q23.

A train moving at 54 km/h crosses a man standing on platform in 12 seconds. Length of train?

Q24.

A particle starts from rest. Acceleration = 5 m/s² Find distance travelled during 4th second.

Q25. ⭐ NEET Challenge

A particle moves according to x = 5 + 4t + 2t² Find
  1. Position after 6 s
  2. Velocity after 6 s
  3. Acceleration
  4. Distance covered between 2 s and 6 s
Practice Rule
  • Attempt all questions without looking at formulas.
  • Write complete steps.
  • Time yourself (45 minutes).
  • Target Score : 25/25
NEET Physics - Motion in One Dimension | Supplementary Part 2

🔥 Supplementary Part 2

Ultra-Hard Motion in One Dimension Numericals (Q26–Q50)

Instructions

  • Difficulty: NEET Advanced
  • Attempt without calculator.
  • Take g = 10 m/s² unless otherwise stated.

Q26

A car accelerates uniformly from 10 m/s to 40 m/s in 12 seconds. Find:
  1. Acceleration
  2. Distance travelled

Q27

A particle moves with velocity v = 8 + 3t. Find displacement during first 10 seconds.

Q28

A train moving at 90 km/h crosses a pole in 18 s. Find length of train.

Q29

A ball is projected vertically upward with speed 50 m/s. Find:
  1. Maximum height
  2. Total time of flight

Q30

A body covers:
  • 120 m at 6 m/s
  • 180 m at 9 m/s
Find average speed.

Q31

Two cars move in the same direction. Car A = 18 m/s Car B = 24 m/s Initial gap = 240 m. Find time taken by B to overtake A.

Q32

A particle starts from rest with acceleration 4 m/s². Find distance travelled during the 8th second.

Q33

A cyclist slows uniformly from 12 m/s to rest in 6 s. Find stopping distance.

Q34

A particle moves:
  • 40 m North
  • 30 m East
  • 40 m South
Find displacement.

Q35

Velocity equation: v = 24 − 4t Find:
  1. Time to stop
  2. Distance travelled

Q36

A freely falling stone reaches the ground with velocity 60 m/s. Find height of the tower.

Q37

A train of length 180 m crosses a bridge of length 420 m in 24 s. Find speed of train.

Q38

A body moves according to x = 3t² + 2t + 5. Find velocity at t = 8 s.

Q39

A car travels:
  • 100 km at 50 km/h
  • 150 km at 75 km/h
Find average speed.

Q40

Two trains of lengths 250 m and 150 m move in opposite directions at 18 m/s and 22 m/s. Find crossing time.

Q41

A particle starts from rest. Acceleration = 6 m/s². Find displacement after 15 seconds.

Q42

A ball is thrown downward from a building with velocity 15 m/s. It reaches ground in 5 s. Find height of building.

Q43

A particle covers one-fourth distance at 12 m/s and remaining distance at 24 m/s. Find average speed.

Q44

Position equation: s = 2t³ − 5t² + 8. Find velocity at t = 3 s.

Q45

A train moving at 54 km/h overtakes another moving at 36 km/h. Both trains are 150 m long. Find overtaking time.

Q46

A body starts with velocity 20 m/s and acceleration 3 m/s². Find velocity after travelling 150 m.

Q47

A particle moves:
  • 100 m East
  • 60 m West
  • 20 m East
  • 40 m West
Find:
  1. Total distance
  2. Displacement

Q48

A stone is thrown upward from a cliff of height 80 m with speed 30 m/s. Find time taken to hit the ground.

Q49

A particle has acceleration a = 4 m/s². Initial velocity = 6 m/s. Find displacement in first 12 s.

Q50 ⭐ NEET Challenge

Position equation: x = 10 + 6t + 3t² Find:
  1. Position at t = 8 s
  2. Velocity at t = 8 s
  3. Acceleration
  4. Distance travelled between 4 s and 8 s

Self Evaluation

Score Performance
23–25 Excellent (NEET Top Rank Level)
18–22 Very Good
12–17 Good, Needs Practice
Below 12 Revise Theory & Formulae
NEET Physics Mock Test - Motion in One Dimension (Part 3)

🔥 NEET Physics Mock Test

Motion in One Dimension (Part 3)

Total Questions : 45
Time : 45 Minutes
Marks : 180
Correct : +4
Wrong : −1

Section A (MCQs)

Q1. SI unit of displacement is

A) m/s
B) m
C) km
D) s

Q2. Distance is a

A) Vector
B) Scalar
C) Tensor
D) None

Q3. Velocity can become zero during upward motion of a projectile at

A) Highest point
B) Lowest point
C) Throughout
D) Never

Q4. Average velocity equals average speed when

A) Circular path
B) Straight line without changing direction
C) Closed path
D) Random motion

Q5. Which quantity may be zero even when distance is not zero?

A) Speed
B) Time
C) Displacement
D) Velocity

Q6. A body starts from rest. Initial velocity is

A) 1 m/s
B) 10 m/s
C) 0 m/s
D) −1 m/s

Q7. Uniform velocity means

A) Constant speed only
B) Constant velocity
C) Variable speed
D) Variable direction

Q8. Unit of acceleration

A) m
B) m/s
C) m/s²
D) km/h

Q9. Graph of uniform motion is

A) Straight line
B) Circle
C) Parabola
D) Hyperbola

Q10. Which is a vector?

A) Speed
B) Distance
C) Velocity
D) Time

Q11. A car moves 20 m East then 20 m West. Displacement is

A)40 m B)20 m C)0 D)10 m

Q12. Average speed is

A)Total Distance/Total Time B)Displacement/Time C)v²-u² D)None

Q13. Motion along straight line is called

A)Rectilinear B)Circular C)Rotational D)Projectile

Q14. Retardation is

A)Positive acceleration B)Negative acceleration C)Zero acceleration D)Infinite acceleration

Q15. Speedometer measures

A)Velocity B)Distance C)Instantaneous Speed D)Average Speed

Q16. Odometer measures

A)Speed B)Distance C)Acceleration D)Velocity

Q17. Motion is always

A)Absolute B)Relative C)Constant D)Uniform

Q18. A freely falling body has acceleration

A)g B)0 C)2g D)Depends on mass

Q19. Unit of velocity

A)m B)m/s C)m/s² D)km

Q20. Equation v=u+at is valid for

A)Variable acceleration B)Constant acceleration C)Circular motion D)Random motion

Q21. Which quantity is never negative?

A)Velocity B)Displacement C)Speed D)Acceleration

Q22. Area under velocity-time graph gives

A)Acceleration B)Distance/Displacement C)Speed D)Force

Q23. Slope of displacement-time graph gives

A)Acceleration B)Velocity C)Force D)Momentum

Q24. Slope of velocity-time graph gives

A)Displacement B)Acceleration C)Time D)Distance

Q25. A body moving with constant velocity has

A)Zero acceleration B)Maximum acceleration C)Infinite acceleration D)Variable acceleration

Q26. Graph of rest on displacement-time graph is

A)Horizontal line B)Vertical line C)Curve D)Circle

Q27. SI unit of time

A)Hour B)Second C)Minute D)Day

Q28. Which is scalar?

A)Velocity B)Acceleration C)Distance D)Displacement

Q29. Initial velocity symbol

A)s B)t C)u D)v

Q30. Final velocity symbol

A)u B)a C)v D)s


Section B (Assertion-Reason)

Q31. Motion is relative.
Reason: There is no absolute rest.
Q32. Average speed is always less than average velocity.
Reason: Speed is scalar.
Q33. Displacement may be zero while distance is not zero.
Reason: Distance is scalar.
Q34. Constant speed always means constant velocity.
Reason: Direction may change.
Q35. Uniform acceleration means equal change in velocity in equal intervals of time.

Section C (Numericals)

Q36. A body starts from rest with acceleration 5 m/s². Find velocity after 8 s.
Q37. A train moving at 20 m/s travels for 30 s. Find distance.
Q38. A body moves 60 m East then 80 m West. Find displacement.
Q39. A stone is dropped from height 45 m. Find time to reach ground.
Q40. Find average speed if a car travels 120 km in 2 hours.
Q41. Find displacement using s=ut+½at² where u=10 m/s, a=2 m/s², t=5 s.
Q42. Find acceleration if velocity changes from 10 m/s to 30 m/s in 4 s.
Q43. A train of length 180 m crosses a pole in 12 s. Find speed.
Q44. A ball is thrown upward with 20 m/s. Find maximum height.
Q45. A body moves with velocity equation v=6+2t. Find velocity after 8 s.

OMR Answer Sheet

QAns QAns QAns
1___16___31___
2___17___32___
3___18___33___
4___19___34___
5___20___35___
6___21___36___
7___22___37___
8___23___38___
9___24___39___
10___25___40___
11___26___41___
12___27___42___
13___28___43___
14___29___44___
15___30___45___
NEET Physics - Motion in One Dimension | Part 4 Answer Key

🔥 NEET Physics

Part 4 – Answer Key & Step-by-Step Solutions


Section A (MCQs)

Q Answer Q Answer Q Answer
1B11C21C
2B12A22B
3A13A23B
4B14B24B
5C15C25A
6C16B26A
7B17B27B
8C18A28C
9A19B29C
10C20B30C

Section B (Assertion–Reason)

Question Correct Option
31 A (Both true, Reason correctly explains)
32 D (Assertion false, Reason true)
33 B (Both true, Reason not correct explanation)
34 D (Assertion false, Reason true)
35 A (Both true, Reason correctly explains)

Section C (Numericals)

Q36

Given u = 0 m/s a = 5 m/s² t = 8 s

v = u + at
v = 0 + 5 × 8

Answer = 40 m/s
Q37

Distance = Speed × Time
= 20 × 30

Answer = 600 m
Q38

East = +60 West = -80

Displacement = 60 - 80 = -20 m

Answer = 20 m West
Q39

s = 45 m u = 0 g =10

45 = 5t²
t² =9
t =3 s

Answer = 3 s
Q40

Average Speed =120/2

Answer =60 km/h
Q41

s = ut + ½at²
=10×5 + ½×2×25
=50+25

Answer =75 m
Q42

a=(30−10)/4
=20/4

Answer =5 m/s²
Q43

Speed =180/12

Answer =15 m/s
Q44

Maximum Height H=u²/2g
=20²/(20)
=20 m

Answer =20 m
Q45

v=6+2t
=6+16
Answer =22 m/s

Score Analysis

Marks Performance
170–180 Outstanding ⭐⭐⭐⭐⭐
150–169 Excellent
120–149 Very Good
90–119 Good
Below 90 Needs Revision
Common Mistakes in NEET Motion in One Dimension
  • Confusing distance with displacement.
  • Using average velocity instead of average speed.
  • Incorrect sign convention (+ and -).
  • Using wrong kinematic equation.
  • Mixing km/h and m/s units.
  • Ignoring direction in vector quantities.
  • Calculation mistakes in free-fall problems.
NEET Physics - Motion in One Dimension | Part 5 (PYQs)

🔥 Part 5

Previous Year Question Bank (NEET / AIPMT / AIIMS Style)

This section contains NEET-style questions inspired by previous exam patterns. They are designed for practice and concept building.


Q1. A body moves 10 m east and then 10 m west. What is its displacement?

A) 20 m   B) 10 m   C) 0 m   D) 5 m
Answer: C (0 m)
Q2. Which of the following is a scalar quantity?

A) Velocity B) Acceleration C) Distance D) Displacement
Answer: C
Q3. SI unit of acceleration is

A) m B) m/s C) m/s² D) km/h
Answer: C
Q4. A car starts from rest with acceleration 4 m/s². Find velocity after 5 s.
Answer: 20 m/s
Q5. A train moving at 25 m/s crosses a pole in 8 s. Find length of train.
Answer: 200 m
Q6. A body falls freely for 4 s. Find its velocity on reaching the ground.
Answer: 40 m/s
Q7. Average speed is defined as A) Distance / Time B) Displacement / Time C) Velocity / Time D) None
Answer: A
Q8. Which graph represents uniform motion?
Answer: Straight line on displacement–time graph
Q9. A body moves with constant velocity. Its acceleration is
Answer: Zero
Q10. A stone is thrown upward with speed 30 m/s. Find maximum height.
Answer: 45 m

🔥 PYQ Practice Set (Without Answers)

  1. A body covers 240 m in 30 s. Find average speed.
  2. A car accelerates from 10 m/s to 30 m/s in 5 s. Find acceleration.
  3. Define displacement with one example.
  4. Differentiate between speed and velocity.
  5. A particle moves according to x = 4 + 5t + 2t². Find velocity at t = 6 s.
  6. A train of length 250 m crosses a bridge of length 350 m in 24 s. Find speed.
  7. A freely falling body reaches the ground in 8 s. Find height.
  8. State any two differences between distance and displacement.
  9. Find stopping distance of a car moving at 30 m/s if retardation is 5 m/s².
  10. Find average speed if equal distances are covered at 20 km/h and 30 km/h.

🔥 Formula Revision Sheet

  • v = u + at
  • s = ut + ½at²
  • v² = u² + 2as
  • Average Speed = Total Distance / Total Time
  • Average Velocity = Total Displacement / Total Time
  • Distance = Speed × Time
  • Acceleration = (v − u) / t

🎯 NEET Rapid Revision

  • Motion is relative.
  • Distance is scalar.
  • Displacement is vector.
  • Speed is scalar.
  • Velocity is vector.
  • Acceleration can be positive or negative.
  • Retardation = Negative acceleration.
  • Slope of displacement–time graph = Velocity.
  • Slope of velocity–time graph = Acceleration.
  • Area under velocity–time graph = Displacement.

Uniformly Accelerated Motion Class 11 Physics Notes | NEET & JEE MCQs

 - Dr.Sanjaykumar Pawar   Uniformly Accelerated Motion (1-D) Physics Notes, Formulas & NEET Questions  Uniformly Accelerated Motion (1-D...