Motion in One Dimension – Rest, Motion & Frame of Reference (NEET Notes)
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| Motion in One Dimension – Complete NEET Physics Notes on Frame of Reference, Distance, Displacement, Rest and Motion. |
1. Can the Distance Between Two Places Be Fixed?
Example
Question: What is the distance between City A and City B?
Answer: This is an incomplete (incorrectly framed) question because the distance depends on the path or route taken.
For example:
- Route 1 = 1050 km
- Route 2 = 1510 km
Therefore, distance depends on the path followed.
Important: Always specify the route while asking about distance.
2. Frame of Reference
Definition
A frame of reference is a place or point from where we observe the position or motion of an object.
The person who makes the observation is called the observer.
Example
A student is standing on the roadside and watching a moving bus.
- Road = Frame of reference
- Student = Observer
3. Position
Definition
The position of an object is its location with respect to a frame of reference.
Example
A bicycle is parked 10 m from a tree.
Here,
- Tree = Frame of reference
- Bicycle = Object
4. Rest
Definition
An object is said to be at rest if its position does not change with time with respect to the chosen frame of reference.
Example
A school bag kept on a classroom desk is at rest with respect to the desk.
Position
^
|
|──────────────
|
+---------------------> Time
Position remains constant.
5. Motion
Definition
An object is said to be in motion if its position changes with time with respect to the chosen frame of reference.
Example
A car moving on a highway is in motion with respect to the road.
Position
^
| /
| /
| /
+---------------------> Time
Position changes with time.
Relative Nature of Rest and Motion
Rest and motion are relative terms, not absolute.
They depend on the frame of reference.
Example
Suppose:
- Student A is sitting inside a moving bus.
- Student B is sitting beside Student A.
- A traffic police officer is standing on the roadside.
Then:
- Student A is at rest with respect to Student B.
- Student B is at rest with respect to Student A.
- Student A is in motion with respect to the traffic police officer.
- Student B is also in motion with respect to the traffic police officer.
Thus, the same object can be at rest for one observer and in motion for another observer.
Important NEET Points
- Frame of Reference: Place from where observation is made.
- Observer: Person making the observation.
- Position: Location of an object with respect to the frame of reference.
- Rest: Position does not change with time.
- Motion: Position changes with time.
- Distance depends on the path taken.
- Rest and motion are relative concepts.
- There is no absolute rest or absolute motion in the universe.
NEET Quick Revision
- Frame of Reference → Point from where observation is made.
- Observer → Person who observes.
- Position → Location relative to the reference point.
- Rest → Position remains unchanged with time.
- Motion → Position changes with time.
- Distance → Depends on the path followed.
- Rest and Motion → Relative, not absolute.
Motion in One Dimension – Distance and Displacement (NEET Notes)
1. Observer Always Assumed to be at Rest
Definition
While studying motion, the observer is always assumed to be at rest with respect to the chosen frame of reference.
Example
A student is sitting inside a moving bus and asks,
"Sir, when will Delhi come?"
The teacher replies,
"Delhi is not coming. Our bus is moving towards Delhi."
Although it appears that Delhi is coming closer, actually the bus is moving, while Delhi is at rest with respect to the Earth.
Important Point
- Motion is always described with respect to an observer.
- The observer is usually considered to be at rest.
2. Distance
Definition
Distance is the actual length of the path travelled by an object.
OR
Distance is the total path covered by an object during its motion.
Formula
Distance = Actual Path Length
Characteristics of Distance
- It depends on the path taken.
- It is a Scalar Quantity (only magnitude, no direction).
- It is always positive or zero.
- It cannot be negative.
- SI Unit = metre (m).
- It is always greater than or equal to displacement.
- Scalar quantities are added by simple algebraic addition.
Example 1
A person walks
- 3 m forward
- then 4 m forward
Distance = 3 + 4 = 7 m
Example 2
A person walks along three different paths between the same two points.
Path A = 10 m
Path B = 15 m
Path C = 18 m
Distance depends on which path is chosen.
3. Displacement
Definition
Displacement is the shortest straight-line distance between the initial position and the final position of an object.
OR
Displacement is the change in the position of an object.
Formula
Displacement = Final Position − Initial Position
Characteristics of Displacement
- It depends only on the initial and final positions.
- It does not depend on the path taken.
- It is a Vector Quantity (has magnitude and direction).
- It can be positive, negative, or zero.
- SI Unit = metre (m).
- To calculate displacement, only the initial position and final position are required.
Example 1
A person walks
- 3 m east
- then 4 m east
Distance = 7 m
Displacement = 7 m east
Since there is no change in direction,
Distance = Displacement
Example 2
A person walks
- 3 m east
- then 4 m west
Distance = 3 + 4 = 7 m
Displacement = 1 m west
Here,
Distance > Displacement
Example 3
A person starts from point A, walks around a circular park, and returns to point A.
Distance = Circumference of the park
Displacement = 0
Because the initial and final positions are the same.
4. Relation Between Distance and Displacement
Case 1: Straight-Line Motion (No Change in Direction)
Example
3 m → + 4 m →
Distance = 7 m
Displacement = 7 m
Distance = Displacement
Case 2: Motion with Change in Direction
Example
3 m → then 4 m ←
Distance = 7 m
Displacement = 1 m
Distance > Displacement
Important NEET Points
| Distance | Displacement |
|---|---|
| Actual path length | Shortest straight-line distance |
| Scalar quantity | Vector quantity |
| Depends on path | Does not depend on path |
| Always positive or zero | Can be positive, negative, or zero |
| Cannot be negative | Can be negative |
| Distance ≥ Displacement | Displacement ≤ Distance |
| Unit = metre (m) | Unit = metre (m) |
NEET Quick Revision
- Observer → Usually assumed to be at rest.
- Distance → Actual path travelled.
- Displacement → Shortest straight-line distance between initial and final positions.
- Distance depends on path.
- Displacement depends only on initial and final positions.
- Distance is a scalar quantity.
- Displacement is a vector quantity.
- Distance is always greater than or equal to displacement.
- Distance = Displacement only when the object moves in a straight line without changing direction.
Motion in One Dimension - Distance & Displacement (NEET Level)
Concept Questions with Solutions
A) Distance = |Displacement|
B) Distance < |Displacement|
C) Distance ≥ |Displacement|
D) Distance ≤ |Displacement|
Explanation: Distance is actual path length, while displacement is shortest straight-line distance between initial and final points. So distance is always greater than or equal to displacement.
A) Distance = |Displacement|
B) Distance > |Displacement|
C) Distance < |Displacement|
D) None
Explanation: When motion is in a straight line without reversing direction, actual path equals shortest path, so distance equals magnitude of displacement.
Distance = 4 + 3 = 7 m
Displacement = 7 m east
Explanation: Both motions are in same direction, so distance = displacement.
Distance = 6 + 4 = 10 m
Displacement = 2 m east
Explanation: Distance adds total path. Displacement = final - initial = 6 - 4 = 2 m east.
Explanation: It depends on initial and final positions and includes direction (positive or negative in 1D).
Explanation: Distance is scalar and represents actual path length, so it is always positive or zero.
Distance = circumference of circle
Displacement = 0
Explanation: Final position = initial position, so displacement is zero but path is not zero.
Explanation: Motion is always relative to a chosen observer.
Explanation: An object may appear at rest for one observer and in motion for another.
Distance = 15 m
Displacement = 15 m
Explanation: Straight-line motion without change in direction makes distance equal to displacement.
Key Formulas
- Distance = Actual path length
- Displacement = Final position - Initial position
- |Displacement| ≤ Distance
Important Points
- Distance is scalar
- Displacement is vector
- Distance depends on path
- Displacement depends only on endpoints
Distance = 3 + 4 = 7 m
Displacement = √(3² + 4²) = √25 = 5 m (north-east direction)
Explanation:
Distance is total path length (scalar), so we simply add.
Displacement is shortest straight-line distance, so we use Pythagoras theorem because motion is at right angle.
Distance = 10 + 10 = 20 m
Displacement = 0 m
Explanation:
The object returns to its starting point, so final position = initial position.
Hence displacement is zero but distance is non-zero.
Explanation: If an object returns to its starting point, displacement becomes zero, but it still covers some distance.
Explanation: Delhi is at rest with respect to Earth. The train is moving towards Delhi. Motion depends on frame of reference.
Displacement = 8 - 3 = 5 m east
Explanation: Direction matters in displacement. East is positive, west is negative in 1D motion.
Because distance is actual path and displacement is shortest path.
Explanation: Any curved or back-and-forth motion increases path length, so distance ≥ displacement always.
Displacement = diameter = 2 × 7 = 14 m
Explanation: In half circle, initial and final points are opposite ends of diameter.
Explanation: Displacement is shortest distance, so it can never exceed actual path length.
Distance = 5 + 5 + 5 = 15 m
Displacement = 5 m east
Explanation: Total path is added for distance, but final position is 5 m east of start.
Explanation: All motion is described relative to the observer (frame of reference).
Distance = 12 + 5 = 17 m
Displacement = 12 - 5 = 7 m north
Explanation:
Distance is total path length (scalar).
Displacement depends on direction, so we subtract opposite directions.
Displacement = √(6² + 8²) = √(36 + 64) = √100 = 10 m (north-east)
Explanation:
Motion is at right angle, so we apply Pythagoras theorem.
Explanation:
Even if the object moves, if final position = initial position, displacement becomes zero.
Distance = Displacement = 20 m
Explanation:
In straight-line motion without changing direction, path length equals shortest distance.
Explanation:
Distance is scalar, so it has only magnitude and no direction.
Explanation:
Distance is actual path length, so it is always positive or zero.
Explanation:
Final position is same as initial position, so displacement is zero.
Explanation:
Displacement is a length quantity, so its SI unit is metre.
Explanation:
They are equal only in straight-line motion without change in direction.
Distance = 4 + 4 + 4 + 4 = 16 m
Displacement = 0 m
Explanation:
Distance is total perimeter, but displacement is zero because initial and final positions are same.
Displacement = √(18² + 24²) = √(324 + 576) = √900 = 30 m (north-east)
Explanation:
Since motion is in two perpendicular directions, we use Pythagoras theorem to find shortest distance.
Distance = 15 + 15 = 30 m
Displacement = 0 m
Explanation:
The object returns to its starting point, so displacement is zero.
Explanation:
Distance is actual path length and cannot be less than shortest straight-line distance.
Displacement = (7 + 7 - 7) = 7 m east
Explanation:
Take east as positive and west as negative, then add algebraically.
Explanation:
Motion is always relative to a chosen reference point or observer.
Explanation:
Relative motion inside the bus is zero, so passenger feels at rest.
Explanation:
Initial and final positions are same, so displacement is zero.
Explanation:
Displacement has both magnitude and direction.
Explanation:
Distance is total path length, so we add magnitudes.
Explanation:
Net movement = 12 - 9 = 3 m towards west.
Distance = 10 + 6 + 10 = 26 m
Displacement = 6 m north
Explanation:
Distance is total path length (scalar), so we add all parts.
East and west cancel each other (10 m east and 10 m west), leaving only 6 m north as net displacement.
Explanation:
Final position is same as initial position, so displacement becomes zero.
Explanation:
Distance depends on actual route followed, so different paths give different values.
Explanation:
Displacement can be positive, negative, or zero depending on direction in 1-D motion.
Explanation:
In straight-line motion without reversing direction, path length equals shortest distance.

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