Sunday, June 21, 2026

Motion Under Gravity (Vertical Motion) NEET Notes with Solved Examples

Motion Under Gravity - Easy NEET Notes

Motion Under Gravity (Vertical Motion)

Easy NEET Notes

1. Situation in Figure

A ball is thrown vertically upward from the top of a building.

  • Height of building = 25 m
  • Initial velocity of ball = 20 m/s upward
  • Acceleration due to gravity acts downward
  • Take upward direction as positive

Therefore:

  • Initial velocity → u = +20 m/s
  • Acceleration → a = -10 m/s²
Gravity is always downward.

PART 1: Motion from A to B (Upward Motion)

At highest point B:

  • Final velocity becomes zero
  • Because the ball stops for a moment before coming down

Use first equation of motion:

v = u + at

Substitute values:

0 = 20 + (-10)t
0 = 20 - 10t
10t = 20
t = 2 s

Conclusion

t₁ = 2 s

Time taken to go upward = 2 seconds

PART 2: Motion from B to C (Falling Down)

Now the ball falls from highest point to ground.

At point B:

  • Initial velocity = 0
  • Acceleration = -10 m/s²

Maximum height above ground:

25 + 20 = 45 m

(25 m building + 20 m rise)

Use second equation of motion:

y = y₀ + v₀t + 1/2 at²

Substitute values:

0 = 45 + 0 + 1/2(-10)t²
0 = 45 - 5t²
5t² = 45
t² = 9
t = 3 s

Conclusion

t₂ = 3 s

Time to fall downward = 3 seconds

Total Time of Flight

T = t₁ + t₂
T = 2 + 3
T = 5 s

Final Answer

5 s

Total time taken by the ball to hit ground.

SECOND METHOD (Shortcut Method)

Use whole motion directly.

Given:

  • Initial height = 25 m
  • Final height = 0
  • Initial velocity = 20 m/s
  • Acceleration = -10 m/s²

Use:

y = y₀ + ut + 1/2 at²

Substitute:

0 = 25 + 20t + 1/2(-10)t²
0 = 25 + 20t - 5t²
5t² - 20t - 25 = 0

Solve quadratic equation:

t = 5 s
Same answer obtained.

Important NEET Concepts

1. Sign Convention

If upward is positive:

  • Upward velocity → positive
  • Downward velocity → negative
  • Gravity → negative

2. At Maximum Height

v = 0

Velocity becomes zero only for an instant.

3. Acceleration Due to Gravity

Near Earth:

g = 9.8 m/s²

For NEET numericals often take:

g = 10 m/s²

Free Fall Notes (Example 2.4)

Definition of Free Fall

When an object moves only under gravity (air resistance neglected), it is called free fall.

Important Equations of Free Fall

Velocity-Time Relation

v = u - gt

If object released from rest:

u = 0

Then:

v = -gt

Position-Time Relation

y = y₀ + ut - 1/2 gt²

If released from rest and origin at starting point:

y = -1/2 gt²

Velocity-Position Relation

v² = u² - 2gy

If released from rest:

v² = -2gy

NEET Quick Tips

  • Gravity always acts downward
  • At highest point velocity becomes zero
  • Acceleration never becomes zero
  • Time going up ≠ time coming down if starting and ending heights are different

Most Important Formula Sheet

Equation Formula
First Equation v = u + at
Second Equation s = ut + 1/2 at²
Third Equation v² = u² + 2as

NEET Memory Trick

“UVS”

Remember:

  • (u) → initial velocity
  • (v) → final velocity
  • (s) → displacement
  • (a) → acceleration
  • (t) → time
Use any equation depending on missing quantity.
NEET Physics Easy Notes © 2026

 Motion Under Gravity Class 11 Physics Notes for NEET & JEE 

Physics diagram illustrating motion under gravity with a ball projected vertically upward from a building, showing velocity, acceleration due to gravity, maximum height, and time of flight calculations.
Motion under gravity showing a ball thrown upward from a building with velocity, height, and time calculations.


CBSE Class 11 Physics: Motion Under Gravity Important Questions and Answers

These exam-oriented questions and answers cover MCQs, very short answer questions, short answer questions, long answer questions, assertion-reason questions, fill in the blanks, case study questions, statement-based questions, and match the columns.

Multiple Choice Questions (MCQs)

Question 1

A ball is thrown vertically upward with an initial velocity of 20 m/s. What is its velocity at the highest point?

Options:

  • A) 20 m/s
  • B) 10 m/s
  • C) 0 m/s
  • D) -20 m/s

Answer: C) 0 m/s

Question 2

What is the value of acceleration due to gravity near the Earth's surface?

Options:

  • A) 0 m/s²
  • B) 9.8 m/s² upward
  • C) 9.8 m/s² downward
  • D) 20 m/s² downward

Answer: C) 9.8 m/s² downward

Question 3

At the highest point of vertical motion, the acceleration of the body is:

Options:

  • A) Zero
  • B) 9.8 m/s² upward
  • C) 9.8 m/s² downward
  • D) Infinite

Answer: C) 9.8 m/s² downward


Very Short Answer Questions

Question 1

What is free fall?

Answer: The motion of an object under the influence of gravity alone is called free fall.

Question 2

What is the velocity of a body at the highest point of its motion?

Answer: The velocity becomes zero at the highest point.

Question 3

What is the SI unit of acceleration?

Answer: metre per second squared (m/s²).

Question 4

Does acceleration become zero at the highest point?

Answer: No. Acceleration remains equal to acceleration due to gravity and acts downward.


Short Answer Questions

Question 1

Why does a ball thrown upward slow down as it rises?

Answer: A ball thrown upward slows down because gravity acts downward, opposite to the direction of motion. This downward acceleration continuously decreases the velocity until it becomes zero at the highest point.

Question 2

Write the equations of motion under gravity.

Answer:

For upward positive direction:

v = u − gt

s = ut − ½gt²

v² = u² − 2gs

where:

  • u = initial velocity
  • v = final velocity
  • g = acceleration due to gravity
  • s = displacement
  • t = time

Question 3

Differentiate between velocity and acceleration at the highest point.

Answer:

Velocity Acceleration
Velocity becomes zero. Acceleration remains 9.8 m/s² downward.
Changes direction after reaching the top. Direction remains downward throughout the motion.

Long Answer Questions

Question 1

A ball is thrown vertically upward from the top of a building 25 m high with an initial velocity of 20 m/s. Calculate the total time taken to reach the ground. Take g = 10 m/s².

Answer:

For upward motion:

v = u − gt

0 = 20 − 10t

t = 2 s

Therefore, time to reach the highest point = 2 seconds.

Maximum height gained above the building:

h = u² / 2g

h = (20)² / (2 × 10)

h = 400 / 20

h = 20 m

Total height above ground:

25 + 20 = 45 m

For downward motion:

s = ½gt²

45 = 5t²

t² = 9

t = 3 s

Time of descent = 3 seconds.

Total time of flight:

T = 2 + 3

T = 5 s

Final Answer: The ball reaches the ground after 5 seconds.


Assertion and Reason Questions

Question 1

Assertion (A): Velocity becomes zero at the highest point.

Reason (R): Gravity stops acting at the highest point.

Answer: Assertion is true, but Reason is false because gravity acts continuously throughout the motion.

Question 2

Assertion (A): Acceleration due to gravity remains constant during vertical motion.

Reason (R): Gravity acts continuously downward.

Answer: Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.


Fill in the Blanks

Question 1: The acceleration due to gravity always acts __________.

Answer: downward

Question 2: At the highest point of motion, velocity becomes __________.

Answer: zero

Question 3: Motion under gravity alone is called __________.

Answer: free fall

Question 4: The SI unit of acceleration is __________.

Answer: m/s²


Case Study Questions

A student throws a ball vertically upward from the top of a building with an initial velocity of 20 m/s. The height of the building is 25 m. Assume g = 10 m/s².

Question 1

How much time does the ball take to reach the highest point?

Answer: 2 seconds.

Question 2

What is the maximum height gained above the building?

Answer: 20 metres.

Question 3

What is the total height above the ground at the highest point?

Answer: 45 metres.

Question 4

What is the velocity at the highest point?

Answer: 0 m/s.

Question 5

What is the total time of flight?

Answer: 5 seconds.


Match the Columns

Column A Column B
Highest Point Velocity becomes zero
Free Fall Motion under gravity alone
Acceleration Due to Gravity 9.8 m/s²
SI Unit of Acceleration m/s²

Answers:

  • Highest Point → Velocity becomes zero
  • Free Fall → Motion under gravity alone
  • Acceleration Due to Gravity → 9.8 m/s²
  • SI Unit of Acceleration → m/s²

Important Exam Tip

Remember that at the highest point of vertical motion, velocity becomes zero but acceleration due to gravity remains constant and acts downward. This is one of the most frequently asked concepts in CBSE Class 11 Physics examinations. 


 Internal Links

Motion in a Straight Line Notes

Kinematics Complete Revision Notes

Difference Between Speed and Velocity

Free Fall Numerical Problems

Acceleration Due to Gravity Explained

Vector Basics for NEET

Projectile Motion Notes

NCERT Solutions – Motion in a Straight Line

Important Kinematics Formula Sheet

Previous Year NEET Kinematics Questions

Example 3.4 Solution Explained for Beginners

Block and Trolley System NEET Solution

Newton's Laws of Motion Notes

Work, Energy and Power Notes

Fundamental Forces in Nature Guide

No comments:

Post a Comment

Uniformly Accelerated Motion Class 11 Physics Notes | NEET & JEE MCQs

 - Dr.Sanjaykumar Pawar   Uniformly Accelerated Motion (1-D) Physics Notes, Formulas & NEET Questions  Uniformly Accelerated Motion (1-D...