Sunday, July 12, 2026

Stopping Distance Formula Explained with Solved Examples | Reaction & Braking Distance


 - Dr Sanjay Kumar Pawar

Stopping Distance: Formula, Reaction Distance, Braking Distance & Questions

Educational infographic showing stopping distance formula with reaction distance, braking distance, motion equations, and a solved physics example for beginners.
Stopping Distance consists of Reaction Distance and Braking Distance. Learn the formula with an easy solved example.

Internal Links

  • Motion in a Straight Line
  • Equations of Motion
  • Uniform and Non-Uniform Motion
  • Speed, Velocity and Acceleration
  • Distance and Displacement
  • Newton's Laws of Motion
  • Friction in Physics
  • Work, Energy and Power
  • Projectile Motion
  • Free Fall Equations
  • Average Speed Formula
  • Relative Motion
  • SUVAT Equations
  • Kinematics Notes
  • Physics Formula Sheet
Stopping Distance Notes

Stopping Distance (Reaction Distance + Braking Distance)

What is Stopping Distance?

When a driver sees an obstacle, the car does not stop immediately. The car travels some distance before stopping completely.

The stopping distance has two parts:

  • Reaction Distance → Distance travelled while the driver reacts.
  • Braking Distance → Distance travelled after applying the brakes.
Stopping Distance = Reaction Distance + Braking Distance

S = Sr + Sb

1. Reaction Distance

Sr = u × t

Where

  • u = Initial speed (m/s)
  • t = Reaction time (seconds)

2. Braking Distance

Use the equation of motion:

v² = u² + 2as

When the car stops:

  • v = 0
  • a = Retardation
Therefore,
Sb = u² / 2a

Solved Example

Question

A car is moving with velocity 20 m/s. The driver's reaction time is 0.5 s. The maximum retardation is 4 m/s². Find the stopping distance.

Step 1 : Reaction Distance

Sr = u × t

Sr = 20 × 0.5

Sr = 10 m

Step 2 : Braking Distance

Sb = u² / 2a

= 20² / (2 × 4)

= 400 / 8

= 50 m

Step 3 : Stopping Distance

S = Sr + Sb

= 10 + 50

= 60 m
Answer = 60 m

Shortcut Formula

Stopping Distance

S = ut + u² / 2a

Important Points

  • Reaction distance depends on reaction time.
  • Braking distance depends on speed and braking force.
  • Higher speed means longer stopping distance.
  • Wet roads increase braking distance.
  • Always maintain a safe distance while driving.

Practice Questions

Q1. A car moves at 10 m/s. Reaction time = 1 s Retardation = 5 m/s² Find stopping distance.

Q2. A car moves at 30 m/s. Reaction time = 1 s Retardation = 6 m/s² Find stopping distance.

Q3. A car moves at 15 m/s. Reaction time = 0.4 s Retardation = 3 m/s² Find stopping distance.

Q4. A car moves at 25 m/s. Reaction time = 0.8 s Retardation = 5 m/s² Find stopping distance.

Answers

Question Answer
Q1 20 m
Q2 105 m
Q3 43.5 m
Q4 82.5 m

Quick Revision

Quantity Formula
Reaction Distance Sr = ut
Braking Distance Sb = u² / 2a
Stopping Distance S = Sr + Sb

Memory Trick

Think → Brake → Stop

  • Think = Reaction Distance
  • Brake = Braking Distance
  • Stop = Stopping Distance

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