Showing posts with label Dot Product. Show all posts
Showing posts with label Dot Product. Show all posts

Sunday, July 26, 2026

Vectors and Scalars Notes — CBSE Class 11 & NEET Guide

 - Dr.Sanjaykumar Pawar  

Diagram of three vector arrows of different lengths and directions on a graph-paper background, illustrating magnitude and direction in physics.
Vectors are drawn as arrows — length shows magnitude, arrowhead shows direction.
 


Internal Links

Vectors & Scalars — NEET Field Notes
NEET Physics · Chapter 2

Vectors & Scalars

The quantities that need a direction, the ones that don't, and the one rule that tells them apart. Complete beginner notes with worked diagrams.

3 m/s (tube) 4 m/s (ball) R = 5 m/s 53°
THE TUBE-AND-BALL PROBLEM — a right triangle hiding in a physics question
01 — Foundations

Why physics needs vectors

Mathematics is the language of physics. Some quantities are fully described by just a number. Others refuse to make sense without a direction attached. Splitting these two apart is the entire point of this chapter — and it shows up in almost every numerical on the NEET paper afterward, from projectile motion to electric fields.

02 — The simple ones

Scalars

Definition: quantities completely described by a numerical value (with a unit) alone. No direction is involved, and they combine using ordinary algebra.

Worked example

A system made of two bodies — one of mass 5 kg, the other 2 kg — has a combined mass of:

5 kg + 2 kg = 7 kg

No angles, no diagrams. Just addition. That is the signature of a scalar.

Common scalars: mass, time, temperature, speed, energy, work, power, distance, charge, density.

03 — The directional ones

Vectors

Definition: quantities that need both magnitude and direction for a complete description, and which add according to the geometric triangle law — not plain algebra.

representation 3 m/s 1 m/s 2.5 m/s 1 m/s Longer arrow = larger magnitude. Arrowhead = direction of travel.
FIG. A — vectors drawn to scale: 1 cm ≡ 1 m/s (arbitrary chosen scale)

Anatomy of a vector arrow

PartNameMeaning
Back endTailStarting point
Front endHeadPoints in the direction of the vector
LengthMagnitudeNumerical size, drawn to scale

Notation: written with an arrow on top — $\vec{AB}$, $\vec{v}$ — or in bold print: AB, v, F.

TRAP

Having a direction is not enough. Electric current flows through a wire in a direction — but current does not add up by the triangle rule. Two currents meeting at a junction just add algebraically (Kirchhoff's rule), not geometrically. So current is a scalar, despite having a direction. This exact question appears repeatedly in NEET-level papers.

04 — The addition rule

Triangle law of vector addition

Statement: if two vectors are represented, in magnitude and direction, by two sides of a triangle taken in order, the resultant is given by the third side, taken in the reverse order.

step 1 A B draw AB (first vector)
Draw the first vector, A to B
step 2 A B C tail of BC starts at head B
From B, draw the second vector, B to C
step 3 — the resultant A B C AC = resultant
Join A to C. This is $\vec{AB} + \vec{BC} = \vec{AC}$
RULE

The resultant always runs from the tail of the first vector to the head of the last vector — regardless of how many vectors you chain together, tail-to-head.

05 — Solved numerical

The tube-and-ball problem

A small ball moves inside a long tube at 3 m/s while the tube itself moves at 4 m/s perpendicular to its own length. What is the ball's resultant velocity, as seen from the room?

3 m (tube, t=1s) 4 m (ball) 5 m/s resultant θ = 53°
Pythagoras hiding inside a physics question: 3-4-5 triangle

Solution

In 1 second: tube carries the ball 3 m along its length; the ball also moves 4 m perpendicular to it. The two displacements form a right triangle, so:

R = √(3² + 4²) = √25 = 5 m

Since this happened in 1 s, the resultant velocity is 5 m/s, directed at

θ = tan⁻¹(4/3) = 53°

…from the direction of the tube.

MEMORIZE

The 3–4–5 right triangle (and its cousin 5–12–13) shows up constantly in NEET vector numericals. Spotting it instantly saves calculator time in the exam.

06 — Reference

Quick formula box

ConceptFormula
Resultant magnitudeR = √(A² + B² + 2AB cos θ)
Direction of resultanttan α = B sin θ / (A + B cos θ)
Maximum resultant (θ = 0°)R = A + B
Minimum resultant (θ = 180°)R = |A − B|
Perpendicular vectors (θ = 90°)R = √(A² + B²)

This is the parallelogram-law version of the same triangle rule — NEET numericals usually hand you this formula directly, so both pictures are worth knowing.

07 — Side by side

Scalar vs vector

PropertyScalarVector
NeedsMagnitude + unit onlyMagnitude + unit + direction
Addition ruleOrdinary algebraTriangle / parallelogram law
Examplesmass, speed, work, energy, current, chargedisplacement, velocity, acceleration, force, momentum
SignCan be negative (e.g. temperature)Magnitude always positive; direction shows sense

Last-minute recall

  • Scalar = magnitude + unit. Vector = magnitude + unit + direction + triangle law.
  • Triangle law: tail-to-head arrangement; resultant runs from the very first tail to the very last head.
  • Current has a direction but is still a scalar — it fails the triangle law test.
  • 3-4-5 right triangle → resultant 5, angle 53°. A recurring numerical pattern — recognize it on sight.
  • Vector addition is commutative: $\vec{A}+\vec{B} = \vec{B}+\vec{A}$.
NEET PHYSICS — VECTORS & SCALARS · FIELD NOTES
Vectors & Scalars — CBSE Class 11 Question Bank
CBSE · Class 11 Physics · Ch. Vectors & Scalars

Complete Question Bank

Every CBSE exam format in one place — MCQs, assertion-reason, fill-in-the-blanks, match-the-column, case study, and short/long answers. Tap any question to reveal the answer.

Section A

Very Short Answer Questions

1 mark each — one line / one word answers

1 markQ1. Define a scalar quantity.
Show answer
A scalar is a physical quantity that is completely described by its magnitude (with a proper unit) alone; it has no associated direction. Example: mass, time.
1 markQ2. Define a vector quantity.
Show answer
A vector is a physical quantity that requires both magnitude and direction for its complete description, and which obeys the triangle law of addition.
1 markQ3. Give one example each of a scalar and a vector quantity other than mass and velocity.
Show answer
Scalar: electric charge (or work, energy). Vector: force (or momentum, acceleration).
1 markQ4. Is electric current a vector quantity? Justify in one line.
Show answer
No. Although current has a direction of flow, it does not add according to the triangle law of vector addition, so it is treated as a scalar.
1 markQ5. What is a unit vector?
Show answer
A vector having a magnitude of exactly one, used only to indicate direction. Example: î, ĵ, k̂ along the x, y, z axes.
1 markQ6. What is meant by a null (zero) vector?
Show answer
A vector whose magnitude is zero and whose direction is indeterminate. Example: the resultant of two equal and opposite vectors.
1 markQ7. Can the magnitude of a vector be negative?
Show answer
No. The magnitude of a vector is always a non-negative real number; a negative sign only reverses its direction.
1 markQ8. State whether displacement is a scalar or a vector.
Show answer
Displacement is a vector quantity — it has both magnitude (shortest distance) and direction (from initial to final position).
1 markQ9. Two vectors are said to be equal when — complete the statement.
Show answer
…when they have the same magnitude and the same direction, regardless of their initial points (position).
1 markQ10. What is the angle between two vectors for their resultant to be maximum?
Show answer
0° (vectors acting in the same direction); the resultant magnitude is then A + B.
Section B

Short Answer Questions

2–3 marks each

2 marksQ1. Distinguish between scalar and vector quantities with one example of each.
Show answer
Answer A scalar has magnitude and unit only, and adds by ordinary algebra (e.g., mass: 2 kg + 3 kg = 5 kg). A vector has magnitude, unit, and direction, and adds by the triangle/parallelogram law (e.g., velocity: two velocities at an angle combine geometrically, not by simple addition).
2 marksQ2. Why is electric current not considered a vector quantity even though it has direction?
Show answer
Answer Current has magnitude and a sense of direction along a wire, but two currents meeting at a junction combine algebraically (Kirchhoff's current law), not by the triangle law. Since a valid vector must obey vector addition rules, current fails this test and is classified as a scalar.
3 marksQ3. State the triangle law of vector addition and mention one limitation of representing vectors only graphically.
Show answer
Answer Triangle law: if two vectors are represented in magnitude and direction by two sides of a triangle taken in order, their resultant is represented by the third side taken in the reverse order (tail of first to head of second).

Limitation: a purely graphical (scale-drawing) method is time-consuming and gives limited accuracy compared to the analytical formula R = √(A² + B² + 2AB cosθ), especially for angles that are not simple values.
2 marksQ4. What are equal and negative vectors? Give an example of each.
Show answer
Answer Equal vectors: same magnitude and same direction (e.g., two cars moving at 40 km/h due north). Negative vectors: same magnitude but opposite direction (e.g., $\vec{A}$ and $-\vec{A}$ — a vector and its reverse).
3 marksQ5. Explain resolution of a vector into rectangular components with a labelled reasoning (no diagram needed, describe it).
Show answer
Answer Any vector $\vec{A}$ in the xy-plane can be broken into two mutually perpendicular components: $A_x = A\cos\theta$ along the x-axis and $A_y = A\sin\theta$ along the y-axis, where θ is the angle the vector makes with the x-axis. These components, added vectorially, reproduce the original vector: $\vec{A} = A_x\hat{i} + A_y\hat{j}$. This makes vector algebra (addition/subtraction) far simpler because components along the same axis just add algebraically.
2 marksQ6. Two forces of 3 N and 4 N act on a body at right angles to each other. Find the magnitude of the resultant.
Show answer
Answer Since θ = 90°, R = √(3² + 4²) = √25 = 5 N, directed at tan⁻¹(4/3) = 53° from the 3 N force.
Section C

Long Answer Questions

5 marks each — full derivations expected in exam

5 marksQ1. State and derive the expression for the magnitude and direction of the resultant of two vectors using the parallelogram law of vector addition.
Show answer
Answer (outline) Let $\vec{A}$ and $\vec{B}$ act at angle θ, represented as two adjacent sides OP and OQ of a parallelogram OPRQ from a common point O. The diagonal OR represents the resultant $\vec{R}$.

Drop a perpendicular from R to the extended OP, meeting it at N. In right triangle ONR: ON = A + B cosθ, and NR = B sinθ.

By Pythagoras: R² = (A + Bcosθ)² + (Bsinθ)² ⇒ R = √(A² + B² + 2AB cosθ).

Direction: tanα = NR / ON = B sinθ / (A + B cosθ), where α is the angle the resultant makes with $\vec{A}$.

Special cases: θ=0° gives R=A+B (maximum); θ=180° gives R=|A−B| (minimum); θ=90° gives R=√(A²+B²).
5 marksQ2. Explain the resolution of a vector in a plane into two mutually perpendicular components, and use it to derive the formula for the resultant of two vectors by the component method.
Show answer
Answer (outline) A vector $\vec{A}$ making angle θ with the x-axis has components $A_x = A\cos\theta$, $A_y = A\sin\theta$, so $\vec{A} = A_x\hat{i} + A_y\hat{j}$, and $A = \sqrt{A_x^2+A_y^2}$.

For two vectors $\vec{A} = A_x\hat{i}+A_y\hat{j}$ and $\vec{B}=B_x\hat{i}+B_y\hat{j}$, the resultant is found by adding components along each axis separately:
$R_x = A_x + B_x$, $R_y = A_y + B_y$
$\vec{R} = R_x\hat{i} + R_y\hat{j}$, with magnitude $R = \sqrt{R_x^2 + R_y^2}$ and direction $\theta = \tan^{-1}(R_y/R_x)$.

This component method avoids drawing diagrams for every problem and is the standard technique used in numericals involving 3 or more vectors.
5 marksQ3. Distinguish between scalar (dot) product and vector (cross) product of two vectors, giving their definitions, formulae, and one physical example of each.
Show answer
Answer Scalar (dot) product: $\vec{A}\cdot\vec{B} = AB\cos\theta$, a scalar result. It represents the component of one vector along another. Physical example: Work done, $W = \vec{F}\cdot\vec{d} = Fd\cos\theta$.

Vector (cross) product: $\vec{A}\times\vec{B} = AB\sin\theta\,\hat{n}$, a vector result, where $\hat{n}$ is perpendicular to the plane of $\vec{A}$ and $\vec{B}$ (direction by the right-hand rule). Physical example: Torque, $\vec{\tau} = \vec{r}\times\vec{F}$.

Key differences: dot product is commutative ($\vec{A}\cdot\vec{B}=\vec{B}\cdot\vec{A}$), cross product is anti-commutative ($\vec{A}\times\vec{B}=-\vec{B}\times\vec{A}$); dot product is maximum when vectors are parallel (θ=0°), cross product is maximum when perpendicular (θ=90°).
Section D

Multiple Choice Questions

1 mark each — correct option highlighted in the reveal

Q1. Which of the following is a scalar quantity?
  • A. Momentum
  • B. Electric current
  • C. Force
  • D. Displacement
Show answer
Correct option: B. Electric current — has direction but does not obey the triangle law, so it is a scalar.
Q2. The resultant of two vectors of magnitude 3 and 4 units acting at 90° to each other is:
  • A. 1 unit
  • B. 7 units
  • C. 5 units
  • D. 25 units
Show answer
Correct option: C. 5 units — √(3²+4²) = √25 = 5.
Q3. Two vectors are equal if they have:
  • A. the same magnitude only
  • B. the same direction only
  • C. the same magnitude and direction
  • D. the same initial point
Show answer
Correct option: C. the same magnitude and direction.
Q4. The maximum number of components a vector can be resolved into is:
  • A. Exactly two
  • B. Exactly three
  • C. Any number, but two mutually perpendicular components are most commonly used
  • D. Only one
Show answer
Correct option: C — a vector can be resolved into any number of components, but resolving into two (or three, in 3D) mutually perpendicular components is standard practice.
Q5. If $\vec{A} + \vec{B} = \vec{A} - \vec{B}$, then:
  • A. $\vec{A} = 0$
  • B. $\vec{B} = 0$
  • C. Both are zero
  • D. $\vec{A} = \vec{B}$
Show answer
Correct option: B. $\vec{B}=0$ — the equation simplifies to 2$\vec{B}$ = 0.
Q6. A unit vector has:
  • A. Magnitude 1 and no unit
  • B. Magnitude equal to the vector it represents direction for
  • C. Zero magnitude
  • D. Magnitude 10
Show answer
Correct option: A. Magnitude 1 and no unit — it is dimensionless and purely indicates direction.
Q7. The dot product of two mutually perpendicular vectors is:
  • A. Maximum
  • B. Equal to AB
  • C. Zero
  • D. Negative
Show answer
Correct option: C. Zero — since cos 90° = 0.
Section E

Assertion & Reason

Each question has an Assertion (A) and a Reason (R). Choose the correct option:

  • (a) Both A and R are true, and R is the correct explanation of A
  • (b) Both A and R are true, but R is NOT the correct explanation of A
  • (c) A is true, R is false
  • (d) A is false, R is true
Q1. Assertion (A): Electric current is not a vector quantity.
Reason (R): Electric current does not obey the triangle law of vector addition.
Show answer
Correct option: (a) — both true, and R correctly explains A; current has direction but fails the addition test required of vectors.
Q2. Assertion (A): The magnitude of the resultant of two vectors can never be less than the difference of their magnitudes.
Reason (R): The resultant is minimum when the two vectors act in the same direction.
Show answer
Correct option: (c) — A is true (minimum resultant = |A−B|), but R is false: the resultant is minimum when vectors act in opposite directions (θ = 180°), not the same direction.
Q3. Assertion (A): Two vectors of unequal magnitude can never give a zero resultant.
Reason (R): A zero resultant requires the two vectors to be exactly equal in magnitude and opposite in direction.
Show answer
Correct option: (a) — both true and R correctly explains A. Only two vectors of equal magnitude acting in exactly opposite directions can cancel to give a null vector.
Q4. Assertion (A): A physical quantity having both magnitude and direction is always a vector.
Reason (R): Electric current has both magnitude and direction, yet it is a scalar.
Show answer
Correct option: (d) — A is false (having magnitude and direction alone doesn't guarantee vector status; it must also obey the triangle law); R is a true, independent statement that in fact contradicts A.
Q5. Assertion (A): The scalar (dot) product of two vectors can be negative.
Reason (R): cos θ is negative for angles between 90° and 180°.
Show answer
Correct option: (a) — both true, and R correctly explains why A holds.
Section F

Fill in the Blanks

Q1. A quantity having magnitude only and no direction is called a .
Show answer
scalar
Q2. The rear end of a vector arrow is called the , and the front end is called the .
Show answer
tail; head
Q3. Two vectors acting in exactly opposite directions are called vectors.
Show answer
negative
Q4. The resultant of two vectors is maximum when the angle between them is .
Show answer
Q5. The resultant of two vectors is minimum when the angle between them is .
Show answer
180°
Q6. A vector whose magnitude is zero is called a vector.
Show answer
null (zero)
Q7. The dot product of two vectors is also known as the product.
Show answer
scalar
Q8. The cross product of two vectors is also known as the product, and its result is always a .
Show answer
vector; vector (perpendicular to the plane of the two vectors)
Q9. $\hat{i}, \hat{j}, \hat{k}$ are examples of vectors along the x, y, z axes.
Show answer
unit
Q10. The law used to find the resultant of two vectors represented as adjacent sides of a figure from a common point is called the law.
Show answer
parallelogram
Section G

Match the Column

Match Column A (quantity) with Column B (type):

Column AColumn B
1. Mass(p) Vector
2. Displacement(q) Scalar
3. Electric current(r) Vector
4. Force(s) Scalar
Show answer
1 → (q) Scalar  |  2 → (p) Vector  |  3 → (s) Scalar  |  4 → (r) Vector

Match the angle between two vectors (Column A) with the type of resultant (Column B):

Column AColumn B
1. θ = 0°(p) R = |A − B| (minimum)
2. θ = 90°(q) R = A + B (maximum)
3. θ = 180°(r) R = √(A² + B²)
Show answer
1 → (q)  |  2 → (r)  |  3 → (p)
Section H

Statement-Based Questions

Read the statements and choose: (a) Both true, (b) Statement I true, II false, (c) Statement I false, II true, (d) Both false

Q1.

Statement I: Every vector has both magnitude and direction.
Statement II: Every quantity with magnitude and direction is a vector.

Show answer
Correct option: (b) — Statement I is true by definition. Statement II is false, since current disproves it (it fails the triangle law).
Q2.

Statement I: The scalar product of two perpendicular vectors is zero.
Statement II: The vector product of two parallel vectors is zero.

Show answer
Correct option: (a) — Both true. Dot product ∝ cosθ = 0 at 90°; cross product ∝ sinθ = 0 at 0°/180° (parallel).
Q3.

Statement I: Vector addition is commutative.
Statement II: Vector subtraction is commutative.

Show answer
Correct option: (b) — $\vec{A}+\vec{B}=\vec{B}+\vec{A}$ is true, but $\vec{A}-\vec{B} \neq \vec{B}-\vec{A}$ in general, so Statement II is false.
Section I

Case Study Based Question

A student is studying a small ball moving inside a long straight tube. While the ball moves along the length of the tube at a steady speed, the tube itself is being carried across the room, moving in a direction perpendicular to its own length, at a different steady speed. The student wants to determine the actual velocity of the ball as observed by someone standing still in the room (not moving with the tube).

(i) Which law of vector addition should the student use to find the ball's resultant velocity?

Show answer
The triangle law of vector addition (equivalently, the parallelogram law), since the two velocities act at an angle to each other, not along the same line.

(ii) If the tube moves at 3 m/s and the ball moves at 4 m/s relative to the tube, find the magnitude of the resultant velocity.

Show answer
Since the two velocities are perpendicular: R = √(3² + 4²) = √25 = 5 m/s.

(iii) Find the angle the resultant velocity makes with the direction of the tube's motion.

Show answer
θ = tan⁻¹(4/3) = 53° from the direction of the tube's velocity.

(iv) If instead the ball's velocity along the tube were reversed in sense (but same magnitude), would the magnitude of the resultant velocity change?

Show answer
No. Reversing one component's sense changes the resultant's direction, but since the two velocities remain perpendicular with the same magnitudes (3 and 4), the resultant magnitude stays 5 m/s.

CBSE CLASS 11 PHYSICS · VECTORS & SCALARS · COMPLETE QUESTION BANK

Tuesday, June 16, 2026

Scalar Product (Dot Product) Class 11 Physics Notes for NEET

 Scalar Product Explained Easily | NEET Physics Vector Notes

- Dr.Sanjaykumar Pawar 

Educational diagram explaining scalar product or dot product of vectors with angle theta, projection, unit vectors and formula A dot B equals AB cos theta.
Scalar Product (Dot Product) of two vectors showing angle, projection and formula A·B = AB cosθ.




INTERNAL LINK SUGGESTIONS

Introduction to Vectors in Physics

Types of Physical Quantities: Scalars and Vectors

Vector Addition and Subtraction

Resolution of Vectors

Unit Vectors Explained

Position Vector Notes

Cross Product (Vector Product)

Motion in a Plane Notes

Projectile Motion Complete Guide

Laws of Motion Notes

Work, Energy and Power

Rotational Motion Basics

Important Vector Formulas for NEET

NCERT Class 11 Physics Chapter-wise Notes

NEET Physics Formula Handbook


Scalar Product (Dot Product) - NEET Notes

The Scalar Product (Dot Product) - NEET Notes

1. Introduction

  • Physical quantities such as displacement, velocity, acceleration and force are vectors.
  • A vector has both magnitude and direction.
  • We already know how vectors are added and subtracted.
  • Now we study how vectors are multiplied.

Types of Vector Multiplication

  1. Scalar Product (Dot Product) → Produces a scalar quantity.
  2. Vector Product (Cross Product) → Produces a new vector.

In this chapter we study the Scalar Product (Dot Product).


2. Definition of Scalar Product

The scalar product or dot product of two vectors A and B is written as:

A · B = AB cosθ

where:

  • A = Magnitude of vector A
  • B = Magnitude of vector B
  • θ = Angle between vectors A and B
Since A, B and cosθ are scalars, the dot product is also a scalar quantity.

The vectors A and B have directions, but their scalar product has no direction.


3. Geometrical Meaning of Dot Product

A · B = A(B cosθ)

B cosθ is the projection (component) of vector B along vector A.

Therefore:

  • Dot Product = Magnitude of A × Component of B along A
A · B = B(A cosθ)

A cosθ is the projection of vector A along vector B.

  • Dot Product = Magnitude of B × Component of A along B

4. Special Cases of Dot Product

Case 1: θ = 0°

A · B = AB cos0°
A · B = AB

Maximum positive value.

Case 2: θ = 90°

A · B = AB cos90°
A · B = 0

Vectors are perpendicular.

Case 3: θ = 180°

A · B = AB cos180°
A · B = -AB

Maximum negative value.


5. Properties of Scalar Product

A. Commutative Law

A · B = B · A

Changing the order does not change the answer.

B. Distributive Law

A · (B + C) = A · B + A · C

C. Scalar Multiplication

A · (λB) = λ(A · B)

where λ is a real number.


6. Dot Product of Unit Vectors

The unit vectors are:

î , ĵ , k̂
  • î → x-axis direction
  • ĵ → y-axis direction
  • k̂ → z-axis direction

Same Unit Vectors

î · î = 1
ĵ · ĵ = 1
k̂ · k̂ = 1
Same unit vectors → Answer = 1

Different Unit Vectors

î · ĵ = 0
ĵ · k̂ = 0
k̂ · î = 0
Different unit vectors → Answer = 0

7. Cartesian Form of Vectors

A = Ax î + Ay ĵ + Az k̂
B = Bx î + By ĵ + Bz k̂

Then their scalar product is:

A · B = AxBx + AyBy + AzBz
Very Important Formula for NEET

8. Dot Product of a Vector with Itself

A · A = Ax² + Ay² + Az²

Also,

A · A = |A||A| cos0°
A · A = A²

Therefore,

A² = Ax² + Ay² + Az²

Magnitude of vector A:

|A| = √(Ax² + Ay² + Az²)

9. Condition for Perpendicular Vectors

If two vectors are perpendicular:

θ = 90°

Since cos90° = 0:

A · B = 0
If A · B = 0, then vectors A and B are perpendicular (provided neither vector is zero).

NEET Quick Revision

Definition

A · B = AB cosθ

Component Form

A · B = AxBx + AyBy + AzBz

Unit Vector Results

î · î = 1
ĵ · ĵ = 1
k̂ · k̂ = 1
î · ĵ = 0
ĵ · k̂ = 0
k̂ · î = 0

Magnitude Formula

|A| = √(Ax² + Ay² + Az²)

Perpendicular Vectors

A · B = 0

Special Angles

Angle (θ) Dot Product
AB
90° 0
180° -AB
Remember:

Dot Product = Magnitude × Magnitude × cos(angle)

The dot product tells how much one vector acts in the direction of another vector.
CBSE Class 11 Physics - Scalar Product Question Bank

CBSE Class 11 Physics

Chapter: Scalar Product (Dot Product)

A. Multiple Choice Questions (MCQs)

1. The scalar product of two vectors is always a:

(a) Vector    (b) Scalar    (c) Tensor    (d) Matrix

Answer: (b) Scalar

2. The dot product of two perpendicular vectors is:

(a) 1    (b) -1    (c) 0    (d) Infinity

Answer: (c) 0

3. The scalar product formula is:

(a) A × B    (b) A + B    (c) AB cosθ    (d) A − B

Answer: (c) AB cosθ

4. The value of î · ĵ is:

(a) 1    (b) 0    (c) -1    (d) 2

Answer: (b) 0

5. A · A equals:

(a) A²    (b) A    (c) 0    (d) 1

Answer: (a) A²

B. Very Short Answer Questions (1 Mark)

1. Define scalar product.

The scalar product of vectors A and B is defined as: A · B = AB cosθ

2. What is î · î ?

1

3. What is ĵ · k̂ ?

0

4. What is the angle between vectors having zero dot product?

90°

5. Is dot product scalar or vector?

Scalar

C. Short Answer Questions (2–3 Marks)

1. State any two properties of scalar product.

1. A · B = B · A (Commutative Law)
2. A · (B + C) = A · B + A · C (Distributive Law)

2. Find the dot product of A = 2î + 3ĵ and B = 4î + 5ĵ.

A · B = (2×4) + (3×5)
= 8 + 15
= 23

3. Why is scalar product called a scalar quantity?

Because the result of the multiplication has magnitude only and no direction.

D. Long Answer Questions (5 Marks)

1. Define scalar product and explain its geometrical significance.

The scalar product of vectors A and B is:A · B = AB cosθ where θ is the angle between the vectors. Geometrically, B cosθ is the projection of B along A. Therefore, A · B = A(B cosθ) Similarly, A cosθ is the projection of A along B. Thus, scalar product represents the product of the magnitude of one vector and the component of the other vector along it.

2. Derive the Cartesian form of scalar product.

A = Ax î + Ay ĵ + Az k̂ B = Bx î + By ĵ + Bz k̂ Using: î·î = 1 ĵ·ĵ = 1 k̂·k̂ = 1 î·ĵ = ĵ·k̂ = k̂·î = 0 Therefore, A · B = AxBx + AyBy + AzBz Hence proved.

E. Assertion and Reason Questions

Assertion (A): The dot product of two perpendicular vectors is zero.
Reason (R): cos 90° = 0.

Answer: Both A and R are true and R is the correct explanation.

Assertion (A): î · ĵ = 1
Reason (R): î and ĵ are perpendicular.

Answer: Assertion is false but Reason is true.

F. Fill in the Blanks

  1. Scalar product of vectors A and B is __________.
  2. Dot product of perpendicular vectors is __________.
  3. î · î = __________.
  4. ĵ · k̂ = __________.
  5. A · A = __________.
1. AB cosθ
2. Zero
3. 1
4. 0
5. A²

G. True or False

Statement Answer
Dot product gives a vector quantity. False
A · B = B · A True
î · ĵ = 1 False
Dot product can be negative. True
A · A is always positive. True

H. Match the Columns

Column A Column B
î·î 1
î·ĵ 0
A·A
Perpendicular vectors A·B = 0
Answers:
1 → 1
2 → 0
3 → A²
4 → A·B = 0

I. Case Study Questions

Two vectors A and B have magnitudes 5 and 10 units respectively. The angle between them is 60°.

1. What is the value of cos 60°?

1/2

2. Calculate A · B.

A · B = AB cosθ
= 5 × 10 × 1/2
= 25

3. Is the result scalar or vector?

Scalar

4. What will be the dot product if θ = 90°?

0

5. What will be the dot product if θ = 180°?

-50

J. Competency-Based Questions

1. A student claims that if A·B = 0, then vectors are perpendicular. Is the statement correct?

Yes. For non-zero vectors,A·B = AB cosθ = 0 Therefore cosθ = 0 Hence θ = 90°. The vectors are perpendicular.

2. Why is scalar product useful in physics?

It is used in calculating work done, power, projections of vectors and determining angles between vectors.
Scalar Product Mind Map

THE SCALAR PRODUCT (DOT PRODUCT)

THE SCALAR PRODUCT (DOT PRODUCT)
│
├── Introduction
│   │
│   ├── Vectors have
│   │   ├── Magnitude
│   │   └── Direction
│   │
│   ├── Examples
│   │   ├── Displacement
│   │   ├── Velocity
│   │   ├── Acceleration
│   │   └── Force
│   │
│   └── Vector Multiplication
│       ├── Scalar Product (Dot Product)
│       └── Vector Product (Cross Product)
│
├── Definition
│   │
│   ├── A · B = AB cosθ
│   │
│   ├── A = Magnitude of Vector A
│   ├── B = Magnitude of Vector B
│   ├── θ = Angle Between Vectors
│   │
│   └── Result
│       └── Scalar Quantity
│
├── Geometrical Meaning
│   │
│   ├── A · B = A(B cosθ)
│   │   └── B cosθ = Component of B along A
│   │
│   ├── A · B = B(A cosθ)
│   │   └── A cosθ = Component of A along B
│   │
│   └── Dot Product
│       └── Measures Projection
│
├── Special Cases
│   │
│   ├── θ = 0°
│   │   ├── cos0° = 1
│   │   └── A · B = AB
│   │
│   ├── θ = 90°
│   │   ├── cos90° = 0
│   │   └── A · B = 0
│   │
│   └── θ = 180°
│       ├── cos180° = -1
│       └── A · B = -AB
│
├── Properties
│   │
│   ├── Commutative Law
│   │   └── A · B = B · A
│   │
│   ├── Distributive Law
│   │   └── A · (B + C)
│   │       = A · B + A · C
│   │
│   └── Scalar Multiplication
│       └── A · (λB)
│           = λ(A · B)
│
├── Unit Vectors
│   │
│   ├── î → x-axis
│   ├── ĵ → y-axis
│   └── k̂ → z-axis
│
├── Dot Product of Same Unit Vectors
│   │
│   ├── î · î = 1
│   ├── ĵ · ĵ = 1
│   └── k̂ · k̂ = 1
│
├── Dot Product of Different Unit Vectors
│   │
│   ├── î · ĵ = 0
│   ├── ĵ · k̂ = 0
│   └── k̂ · î = 0
│
├── Cartesian Form
│   │
│   ├── A = Ax î + Ay ĵ + Az k̂
│   │
│   ├── B = Bx î + By ĵ + Bz k̂
│   │
│   └── A · B
│       └── AxBx + AyBy + AzBz
│
├── Vector with Itself
│   │
│   ├── A · A
│   │   └── Ax² + Ay² + Az²
│   │
│   ├── A · A = A²
│   │
│   └── Magnitude
│       └── |A|
│           = √(Ax² + Ay² + Az²)
│
├── Perpendicular Vectors
│   │
│   ├── θ = 90°
│   ├── cos90° = 0
│   └── A · B = 0
│
└── NEET Quick Revision
    │
    ├── Formula
    │   └── A · B = AB cosθ
    │
    ├── Component Form
    │   └── AxBx + AyBy + AzBz
    │
    ├── Same Unit Vectors
    │   └── Answer = 1
    │
    ├── Different Unit Vectors
    │   └── Answer = 0
    │
    ├── Magnitude
    │   └── √(Ax² + Ay² + Az²)
    │
    ├── Perpendicular
    │   └── A · B = 0
    │
    └── Remember
        └── Dot Product
            = Magnitude × Magnitude × cosθ

Uniformly Accelerated Motion Class 11 Physics Notes | NEET & JEE MCQs

 - Dr.Sanjaykumar Pawar   Uniformly Accelerated Motion (1-D) Physics Notes, Formulas & NEET Questions  Uniformly Accelerated Motion (1-D...