Showing posts with label Train Crossing Problems. Show all posts
Showing posts with label Train Crossing Problems. Show all posts

Friday, July 10, 2026

Train Crossing Bridge Questions and Answers Class 11 Physics | CBSE & NEET Practice

 - Dr.Sanjaykumar Pawar  

Train Crossing Bridge Numerical Questions with Solutions | Class 11 Physics 

Illustration showing a train crossing a bridge with labeled train length, bridge length, velocity, acceleration, and displacement for Class 11 Physics and NEET preparation.
Train Crossing Bridge Numerical for CBSE Class 11 Physics with Step-by-Step Solution


Internal Links

  1. Motion in a Straight Line Complete Notes
  2. Equations of Motion Explained
  3. Relative Motion Notes
  4. Average Speed and Average Velocity
  5. Instantaneous Velocity Notes
  6. Acceleration Complete Notes
  7. Graphical Analysis of Motion
  8. Kinematics Formula Sheet
  9. Work, Energy and Power Notes
  10. Laws of Motion Complete Notes
  11. NEET Physics Chapter-wise MCQs
  12. CBSE Class 11 Physics Important Questions
  13. Assertion and Reason Questions for Physics
  14. Case Study Questions for Class 11 
  15. NCERT Solutions for Motion in a Straight Line
  16. Previous Year CBSE Physics Questions
  17. NEET Physics Practice Tests
  18. One-Dimensional Motion Numericals
  19. Train Crossing and River Boat Problems
  20. Class 11 Physics Revision Notes
CBSE Class 11 Physics Practice Questions and Answers | Train Crossing Bridge

CBSE Class 11 Physics

Practice Questions and Answers

Topic: Motion in a Straight Line – Train Crossing Bridge with Constant Acceleration


Question 1

A 120 m long train crosses a 480 m long bridge with a constant acceleration of 1 m/s². The train enters the bridge with an initial velocity of 20 m/s.

Find the time taken by the train to completely cross the bridge.

Answer

Given:
  • Length of Train = 120 m
  • Length of Bridge = 480 m
  • Initial Velocity (u) = 20 m/s
  • Acceleration (a) = 1 m/s²
Step 1: Total Distance Covered
Distance = Length of Train + Length of Bridge
s = 120 + 480 = 600 m
Step 2: Apply Equation of Motion
s = ut + ½at²
600 = 20t + ½(1)t²
600 = 20t + 0.5t²
Multiply by 2
1200 = 40t + t²
t² + 40t − 1200 = 0
Factorisation
(t + 60)(t − 20) = 0
Time Taken = 20 s

Question 2

A 150 m long train crosses a 450 m long bridge with constant acceleration 2 m/s². The initial velocity of the train is 10 m/s.

Find the time taken to completely cross the bridge.

Answer

Given:
  • Length of Train = 150 m
  • Length of Bridge = 450 m
  • Initial Velocity = 10 m/s
  • Acceleration = 2 m/s²
Step 1: Calculate Total Distance
s = 150 + 450 = 600 m
Step 2: Apply Equation
600 = 10t + ½(2)t²
600 = 10t + t²
t² + 10t − 600 = 0
Factorisation
(t + 30)(t − 20) = 0
Time Taken = 20 s

Question 3

A 200 m long train crosses a 300 m long bridge. It enters the bridge with a speed of 15 m/s and accelerates uniformly at 1 m/s².

Find the time taken by the train to completely cross the bridge.

Answer

Given:
  • Length of Train = 200 m
  • Length of Bridge = 300 m
  • Initial Velocity = 15 m/s
  • Acceleration = 1 m/s²
Step 1: Total Distance
s = 200 + 300 = 500 m
Step 2: Equation of Motion
500 = 15t + ½(1)t²
500 = 15t + 0.5t²
Multiply by 2
1000 = 30t + t²
t² + 30t − 1000 = 0
Using quadratic formula,
t = 20 s
Time Taken = 20 s

Question 4

A 100 m long train completely crosses a 400 m long bridge. The train enters the bridge with an initial speed of 25 m/s and moves with a constant acceleration of 2 m/s².

Find the time taken by the train to completely cross the bridge.

Answer

Given:
  • Length of Train = 100 m
  • Length of Bridge = 400 m
  • Initial Velocity (u) = 25 m/s
  • Acceleration (a) = 2 m/s²
Step 1: Calculate Total Distance
Distance = Length of Train + Length of Bridge
s = 100 + 400 = 500 m
Step 2: Apply Equation of Motion
s = ut + ½at²
500 = 25t + ½(2)t²
500 = 25t + t²
Rearranging,
t² + 25t − 500 = 0
Using the quadratic formula,
t = 13.9 s (approximately)
Time Taken = 13.9 s

Question 5

A 250 m long train crosses a 350 m long bridge. It enters the bridge with an initial speed of 20 m/s and accelerates uniformly at 2 m/s².

Find the time taken by the train to completely cross the bridge.

Answer

Given:
  • Length of Train = 250 m
  • Length of Bridge = 350 m
  • Initial Velocity = 20 m/s
  • Acceleration = 2 m/s²
Step 1: Total Distance
s = 250 + 350 = 600 m
Step 2: Apply Equation of Motion
600 = 20t + ½(2)t²
600 = 20t + t²
Rearranging,
t² + 20t − 600 = 0
Using the quadratic formula,
t = 15.6 s (approximately)
Time Taken = 15.6 s

Question 6 (Assertion & Reason)

Assertion (A):

To completely cross a bridge, a train travels a distance equal to the sum of the length of the train and the length of the bridge.


Reason (R):

The rear end of the train leaves the bridge only after the front end has already crossed the bridge.

Choose the correct option.

  1. Both A and R are true, and R is the correct explanation of A.
  2. Both A and R are true, but R is not the correct explanation of A.
  3. A is true, but R is false.
  4. A is false, but R is true.

Answer

Correct Option: A. Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.

Explanation:

When a train completely crosses a bridge, its front end first reaches the other end of the bridge. However, the train is considered completely out of the bridge only when its rear end also leaves the bridge. Therefore, the train travels a distance equal to the sum of its own length and the length of the bridge.

Correct Answer: Option A

Question 7 (Very Short Answer)

Why do we add the length of the train and the length of the bridge while solving train crossing problems?

Answer

The train completely crosses the bridge only when its rear end leaves the bridge. Therefore, the front end of the train travels a distance equal to the sum of the train's length and the bridge's length.

Distance = Length of Train + Length of Bridge

Question 8 (Short Answer)

Which equation of motion is generally used when displacement, initial velocity, acceleration, and time are involved in train crossing problems?

Answer

The required equation of motion is:

s = ut + ½at²

Where,

  • s = Displacement
  • u = Initial Velocity
  • a = Acceleration
  • t = Time Taken
Equation Used: s = ut + ½at²

Question 9 (Multiple Choice Question)

A 100 m long train crosses a 500 m long bridge with an initial velocity of 10 m/s and an acceleration of 2 m/s².

The time taken is:

  1. 10 s
  2. 15 s
  3. 20 s
  4. 25 s

Answer

Total Distance
100 + 500 = 600 m
Using
600 = 10t + t²
t² + 10t − 600 = 0
(t + 30)(t − 20) = 0
Correct Option: C (20 s)

Question 10 (Concept-Based Question)

A train takes 20 seconds to completely cross a 500 m long bridge. The train is 100 m long.

Find the total displacement of the front end of the train during crossing.

Answer

The front end of the train travels:
Distance = Length of Train + Length of Bridge
Distance = 100 + 500 = 600 m
Total Displacement = 600 m

CBSE Exam Tips

  • Always calculate the total distance as the length of the train + length of the bridge.
  • Choose the correct equation of motion according to the given data.
  • Write every step clearly to score full marks in CBSE board examinations.
  • Include SI units (m, m/s, s) in every calculation.
  • Highlight the final answer inside a box.


Question 7 (Very Short Answer)

Why do we add the length of the train and the length of the bridge while solving train crossing problems?

Answer

The train completely crosses the bridge only when its rear end leaves the bridge. Therefore, the front end of the train travels a distance equal to the sum of the train's length and the bridge's length.

Distance = Length of Train + Length of Bridge

Question 8 (Short Answer)

Which equation of motion is generally used when displacement, initial velocity, acceleration, and time are involved in train crossing problems?

Answer

The required equation of motion is:

s = ut + ½at²

Where,

  • s = Displacement
  • u = Initial Velocity
  • a = Acceleration
  • t = Time Taken
Equation Used: s = ut + ½at²

Question 9 (Multiple Choice Question)

A 100 m long train crosses a 500 m long bridge with an initial velocity of 10 m/s and an acceleration of 2 m/s².

The time taken is:

  1. 10 s
  2. 15 s
  3. 20 s
  4. 25 s

Answer

Total Distance
100 + 500 = 600 m
Using
600 = 10t + t²
t² + 10t − 600 = 0
(t + 30)(t − 20) = 0
Correct Option: C (20 s)

Question 10 (Concept-Based Question)

A train takes 20 seconds to completely cross a 500 m long bridge. The train is 100 m long.

Find the total displacement of the front end of the train during crossing.

Answer

The front end of the train travels:
Distance = Length of Train + Length of Bridge
Distance = 100 + 500 = 600 m
Total Displacement = 600 m

CBSE Exam Tips

  • Always calculate the total distance as the length of the train + length of the bridge.
  • Choose the correct equation of motion according to the given data.
  • Write every step clearly to score full marks in CBSE board examinations.
  • Include SI units (m, m/s, s) in every calculation.
  • Highlight the final answer inside a box.

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